5. Suppose that Joe is a grocery store clerk. The time X (in minutes) that Joe spends checking out a randomly selected customer has probability density function (pdf) 5x4 ·e-(x/3)5 243 5x1 f (x) 0
5. Suppose that Joe is a grocery store clerk. The time X (in minutes) that Joe spends checking out a randomly selected customer has probability density function (pdf) 5x4 ·e-(x/3)5 243 5x1 f (x) 0
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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![5. Suppose that Joe is a grocery store clerk. The time \( X \) (in minutes) that Joe spends checking out a randomly selected customer has a probability density function (pdf)
\[
f(x) = \frac{5x^4}{243} \cdot e^{-\left(\frac{x}{3}\right)^5} = \frac{5x^4}{243} \cdot \exp \left( -\left( \frac{x}{3} \right)^5 \right), \quad 0 < x < \infty.
\]
What is the probability that Joe will spend at least 4 minutes checking out his next customer?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F653b506a-bf1f-413c-8a44-59b8a78c6c88%2F868a77b3-f1b1-4933-8a5f-c00ce4f997a1%2Fwmgqkep_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Suppose that Joe is a grocery store clerk. The time \( X \) (in minutes) that Joe spends checking out a randomly selected customer has a probability density function (pdf)
\[
f(x) = \frac{5x^4}{243} \cdot e^{-\left(\frac{x}{3}\right)^5} = \frac{5x^4}{243} \cdot \exp \left( -\left( \frac{x}{3} \right)^5 \right), \quad 0 < x < \infty.
\]
What is the probability that Joe will spend at least 4 minutes checking out his next customer?
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