5. Solve using classical methods and the given initial condition. d²x dx dt² dt +2 + x = 5e-2t x(0) = 2, dx - (0) = 1 dt +t

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5. Solve using classical methods and the given initial condition.
d²x dx
+2—+ x = 5e-²t
dx
x(0) = 2, (0) = 1
dt
dt² dt
+ t
Transcribed Image Text:5. Solve using classical methods and the given initial condition. d²x dx +2—+ x = 5e-²t dx x(0) = 2, (0) = 1 dt dt² dt + t
Draw block diagrams for the given equation below using take-off point and summing junctions.
d²x₂ dx₁
+
dt² dt
x3 =
-
X1
Transcribed Image Text:Draw block diagrams for the given equation below using take-off point and summing junctions. d²x₂ dx₁ + dt² dt x3 = - X1
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