5. Solve the IVP: 2 y' +y= -x°y5: y(-1) = 2 A. 16 = y (32x10 - 31x") B. 16 = y*(32x!0 +31x8) C. 16 = y (32x" - 31x") 1D. 16 = y'(32x + 31x10) %3D
5. Solve the IVP: 2 y' +y= -x°y5: y(-1) = 2 A. 16 = y (32x10 - 31x") B. 16 = y*(32x!0 +31x8) C. 16 = y (32x" - 31x") 1D. 16 = y'(32x + 31x10) %3D
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![5. Solve the IVP:
2
y'+y -x'y5: y(-1) = 2
A. 16 = y*(32x10 – 31x")
B. 16 y (32x0 + 31x)
C. 16 = y*(32x" – 31x")
D. 16=y'(32x + 31x10)
%3D
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ac98643-abd1-4db4-8d87-0ab0d8bd266c%2Fe0ff8d30-356e-4de7-a2ca-4c7174ed6f8b%2Fcuedx7o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Solve the IVP:
2
y'+y -x'y5: y(-1) = 2
A. 16 = y*(32x10 – 31x")
B. 16 y (32x0 + 31x)
C. 16 = y*(32x" – 31x")
D. 16=y'(32x + 31x10)
%3D
%3D
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