5. Previously we used the recurrence relation dn+1 = 0.5dn + 200, d₁= 200 and the assumption that dnL to compute the limiting value. Compute L is this way and compare to your answer in 4.

Q: part c parked as wrong answer

A: Mean()=12Standard deviation()=4

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Q: the true answer is $

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A: The given expression        6-23-5+52

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Q: 4. Find the 2"

A: Given problem is :

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A: Option D is correct..

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A: x2=y-2-1=z4

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A: First term, a1 = a= 1 common difference, d= 3

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A: (1) Evaluate ∫-98x-5xdx=?