5. n log? n = 0(n²) 6. n log n 20(n) n 3=

Database System Concepts
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ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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true or false and explain why true or false

5. \( n \log^2 n = O(n^2) \)

6. \( n \log^2 n = 2^{O(n)} \)

This transcription contains mathematical equations typical in algorithm analysis, dealing with asymptotic notation. Here, \( n \) is a variable often representing the size of the input, and \( O \) is the Big O notation used to describe an upper bound on the time complexity of an algorithm.

- In equation 5, \( n \log^2 n = O(n^2) \), it suggests that the function \( n \log^2 n \) grows at a rate that is eventually slower than or equal to that of \( n^2 \).

- In equation 6, \( n \log^2 n = 2^{O(n)} \), it implies that the function \( n \log^2 n \) grows at a rate slower than or equal to an exponential function \( 2^n \).
Transcribed Image Text:5. \( n \log^2 n = O(n^2) \) 6. \( n \log^2 n = 2^{O(n)} \) This transcription contains mathematical equations typical in algorithm analysis, dealing with asymptotic notation. Here, \( n \) is a variable often representing the size of the input, and \( O \) is the Big O notation used to describe an upper bound on the time complexity of an algorithm. - In equation 5, \( n \log^2 n = O(n^2) \), it suggests that the function \( n \log^2 n \) grows at a rate that is eventually slower than or equal to that of \( n^2 \). - In equation 6, \( n \log^2 n = 2^{O(n)} \), it implies that the function \( n \log^2 n \) grows at a rate slower than or equal to an exponential function \( 2^n \).
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