5. Lucy solved the quadratic equation: x² -10x +21 = 0 (x+7) (x+3) = 0 Solutions: x = 7 and x= 3 a) Solve the quadratic equation. b) What was Lucy's error(s)? Explain.
5. Lucy solved the quadratic equation: x² -10x +21 = 0 (x+7) (x+3) = 0 Solutions: x = 7 and x= 3 a) Solve the quadratic equation. b) What was Lucy's error(s)? Explain.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![5. Lucy solved the quadratic equation:
x² -10x +21 = 0
(x+7) (x+3) = 0
Solutions: x = 7 and x= 3
a) Solve the quadratic equation.
b) What was Lucy's error(s)? Explain.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f2a0654-3afd-4631-901a-b31816dc185e%2F131d58af-ea59-431e-a969-8cc89c5cd67a%2Fu6cs0d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Lucy solved the quadratic equation:
x² -10x +21 = 0
(x+7) (x+3) = 0
Solutions: x = 7 and x= 3
a) Solve the quadratic equation.
b) What was Lucy's error(s)? Explain.
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