5. Let A be an m x n matrix with real or complex entries. Use the results in the previous Problem 4 to show that rank(A* A) = rank(AA*) = rank(A), and rank(A) = n if and only if A*A is invertible.
5. Let A be an m x n matrix with real or complex entries. Use the results in the previous Problem 4 to show that rank(A* A) = rank(AA*) = rank(A), and rank(A) = n if and only if A*A is invertible.
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter3: Matrices
Section3.5: Subspaces, Basis, Dimension, And Rank
Problem 63EQ
Related questions
Question
Problem5
![5. Let A be an m x n matrix with real or complex entries. Use the results in the
previous Problem 4 to show that
rank(A*A)
and rank(A) = n if and only if A*A is invertible.
=
rank(AA*) = rank(A),](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e948f6-fd6f-485f-942e-c931230f8579%2F941f2839-6ff7-499b-b51a-6eb7c49b8b5f%2F3oavuy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Let A be an m x n matrix with real or complex entries. Use the results in the
previous Problem 4 to show that
rank(A*A)
and rank(A) = n if and only if A*A is invertible.
=
rank(AA*) = rank(A),
![4. Let T: VW be a linear transformation between finite-dimensional inner product
spaces, and let T*: W→ V be the adjoint of T. Prove the following statements.
1
=
(a) rank(T*T) = rank(T). (Hint: N(T*T) =
Sec. 6.3 Exercise 15(e).)
(b) T is injective if and only if T*T is invertible. (Hint: use (a).)
(c) rank(TT*) rank(T). (Hint: interchange the roles of T and T* in (a), and
recall that rank(T*) = rank(T).)
=
N(T) by Homework 9 Textbook](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e948f6-fd6f-485f-942e-c931230f8579%2F941f2839-6ff7-499b-b51a-6eb7c49b8b5f%2Fl6vhw38_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. Let T: VW be a linear transformation between finite-dimensional inner product
spaces, and let T*: W→ V be the adjoint of T. Prove the following statements.
1
=
(a) rank(T*T) = rank(T). (Hint: N(T*T) =
Sec. 6.3 Exercise 15(e).)
(b) T is injective if and only if T*T is invertible. (Hint: use (a).)
(c) rank(TT*) rank(T). (Hint: interchange the roles of T and T* in (a), and
recall that rank(T*) = rank(T).)
=
N(T) by Homework 9 Textbook
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