5. Let A = a22 a23 be an upper triangular matrix such that the elements on 0 A33. all a12 a13 0 0 X₁ the main diagonal are non-zero and let x = x₂ (a) Solve the equations Ax=0 by starting at the equation for x, and working -- backwards towards the equation for x₁. (So: the equation for x3 is a33x3 = 0⇒x3=0, The equation for x₂ is a22x₂ + a23x3 = 0 and we know that x3 = 0, so x₂ = 0, etc.) 0 (b) Use the same method as in (a) to solve the equations Ax= 1 and Ax= 0 -8- (c) Use the results from (a) and (b) to deduce the inverse matrix A¹.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Can I get solution for part c
5. Let A =
all
0
0
a12 a13
a22 a23
0
A33.
be an upper triangular matrix such that the elements on
X₁
the main diagonal are non-zero and let x = x₂
(a) Solve the equations Ax=0 by starting at the equation for x, and working
(9)
backwards towards the equation for x₁. (So: the equation for x3 is
a33x3 = 0⇒x3=0, The equation for x₂ is a22x₂ + a23x3 = 0 and we know that
x3 = 0, so x₂ = 0, etc.)
0
(b) Use the same method as in (a) to solve the equations Ax= 1 and Ax= 0
(17)
(c) Use the results from (a) and (b) to deduce the inverse matrix A-¹.
Transcribed Image Text:5. Let A = all 0 0 a12 a13 a22 a23 0 A33. be an upper triangular matrix such that the elements on X₁ the main diagonal are non-zero and let x = x₂ (a) Solve the equations Ax=0 by starting at the equation for x, and working (9) backwards towards the equation for x₁. (So: the equation for x3 is a33x3 = 0⇒x3=0, The equation for x₂ is a22x₂ + a23x3 = 0 and we know that x3 = 0, so x₂ = 0, etc.) 0 (b) Use the same method as in (a) to solve the equations Ax= 1 and Ax= 0 (17) (c) Use the results from (a) and (b) to deduce the inverse matrix A-¹.
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