5. Is the response rate for questionnaires affected by including some sort of incentive to respond along with the questionnaire? In one experiment, 110 questionnaires with no incentive re- sulted in 75 being returned, whereas 98 questionnaires that included a chance to win a lottery yielded 66 responses. Test the claim at a = 0.05 that including an incentive will increase the likelihood of a response using classical approach. Please show all 4 steps clearly and interpret your conclusion.

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### Question 5

**Research Question:** Is the response rate for questionnaires affected by including some sort of incentive to respond along with the questionnaire?

#### Experimental Details:

- **Without Incentive:** 
  - Total questionnaires: 110
  - Returned: 75
  
- **With Incentive (chance to win a lottery):**
  - Total questionnaires: 98
  - Returned: 66

#### Task:

Test the claim at a significance level of \(\alpha = 0.05\) that including an incentive will increase the likelihood of a response using the classical approach.

**Instructions:**
Please show all 4 steps clearly and interpret your conclusion.

### Solution Steps (Classical Approach):

1. **State the Hypotheses:**
   - Null Hypothesis (\(H_0\)): There is no difference in the response rates with or without incentive.
   - Alternative Hypothesis (\(H_A\)): The response rate with an incentive is higher than the response rate without incentive.

2. **Choose the Significance Level:**
   - \(\alpha = 0.05\)

3. **Select the Appropriate Test Statistic:**
   - Since we are testing for proportions, we use the Z-test for the difference between two proportions.

4. **Calculate the Test Statistic and P-Value:**

\[ \hat{p}_1 = \frac{75}{110} \approx 0.682 \]
\[ \hat{p}_2 = \frac{66}{98} \approx 0.673 \]

\[ \hat{p} = \frac{75 + 66}{110 + 98} \approx 0.678 \]

\[ z = \frac{\hat{p}_1 - \hat{p}_2}{\sqrt{\hat{p}(1 - \hat{p})\left( \frac{1}{110} + \frac{1}{98} \right)}} \]

Insert the respective values to find the Z-score.

5. **Decision Rule:**
   - Compare the Z-score with the critical value from the Z-table at \(\alpha = 0.05\) for a one-tailed test.

6. **Conclusion:**
   - If the calculated Z value exceeds the critical value, reject \(H_0\) and conclude that offering an incentive indeed increases the response rate.

**Note:** Steps 4 and 5 would require mathematical computation
Transcribed Image Text:### Question 5 **Research Question:** Is the response rate for questionnaires affected by including some sort of incentive to respond along with the questionnaire? #### Experimental Details: - **Without Incentive:** - Total questionnaires: 110 - Returned: 75 - **With Incentive (chance to win a lottery):** - Total questionnaires: 98 - Returned: 66 #### Task: Test the claim at a significance level of \(\alpha = 0.05\) that including an incentive will increase the likelihood of a response using the classical approach. **Instructions:** Please show all 4 steps clearly and interpret your conclusion. ### Solution Steps (Classical Approach): 1. **State the Hypotheses:** - Null Hypothesis (\(H_0\)): There is no difference in the response rates with or without incentive. - Alternative Hypothesis (\(H_A\)): The response rate with an incentive is higher than the response rate without incentive. 2. **Choose the Significance Level:** - \(\alpha = 0.05\) 3. **Select the Appropriate Test Statistic:** - Since we are testing for proportions, we use the Z-test for the difference between two proportions. 4. **Calculate the Test Statistic and P-Value:** \[ \hat{p}_1 = \frac{75}{110} \approx 0.682 \] \[ \hat{p}_2 = \frac{66}{98} \approx 0.673 \] \[ \hat{p} = \frac{75 + 66}{110 + 98} \approx 0.678 \] \[ z = \frac{\hat{p}_1 - \hat{p}_2}{\sqrt{\hat{p}(1 - \hat{p})\left( \frac{1}{110} + \frac{1}{98} \right)}} \] Insert the respective values to find the Z-score. 5. **Decision Rule:** - Compare the Z-score with the critical value from the Z-table at \(\alpha = 0.05\) for a one-tailed test. 6. **Conclusion:** - If the calculated Z value exceeds the critical value, reject \(H_0\) and conclude that offering an incentive indeed increases the response rate. **Note:** Steps 4 and 5 would require mathematical computation
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