5. In the titration of 15.00 mL of 0.200 M of a weak base, B:, (Ko = 7.25 x 10³) with 0.100 M HCI. calculate the pH after the addition of the following volumes of titrant (mL); (a) 0.00 ; (b) 10.00: (c) 15.00 ; (d) 20.90 mb.
5. In the titration of 15.00 mL of 0.200 M of a weak base, B:, (Ko = 7.25 x 10³) with 0.100 M HCI. calculate the pH after the addition of the following volumes of titrant (mL); (a) 0.00 ; (b) 10.00: (c) 15.00 ; (d) 20.90 mb.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.57QE
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![5. In the titration of 15.00 mL of 0.200 M of a weak base, B:, (Kb = 7.25 x 10³) with 0.100 M HCI.
calculate the pH after the addition of the following volumes of titrant (mL); (a) 0.00 ; (b) 10.00:
(c ) 15.00 ; (d) 20.00 mL.
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F545b14c7-252e-4dc1-bbf0-8d70a48f5e6e%2F2b1e9763-3ea3-4f29-a71d-492c5aea1ffa%2Fl2lvkcs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. In the titration of 15.00 mL of 0.200 M of a weak base, B:, (Kb = 7.25 x 10³) with 0.100 M HCI.
calculate the pH after the addition of the following volumes of titrant (mL); (a) 0.00 ; (b) 10.00:
(c ) 15.00 ; (d) 20.00 mL.
%3D
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