5. In Problem 5 use the definition of divisibility to do a direct proof of the theorem. Definition. If a and b are integers with a + 0, we say that a divides b if there is an integer c such that b = ac. When a divides b we say that a is a factor or divisor of b, and b is a multiple of a. The notation alb denotes that a divides b. We write a t b when a does not divide b. Theorem. Let a, b and e be integers, where a #0. Then i) If a | b and a c, then a (b+e); ii) If a | b, then a | be for all integers c; iii) If a | b and b |c, then a | c.

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5. In Problem 5 use the definition of divisibility to do a direct proof of the theorem.
Definition. If a and b are integers with a + 0, we say that a divides b if there is an integer e such
that b = ac. When a divides b we say that a is a factor or divisor of b, and b is a multiple of a. The
notation alb denotes that a divides b. We write a { b when a does not divide b.
Theorem. Let a, b and e be integers, where a + 0. Then
i) If a | b and a c, then a | (b+c);
ii) If a | b, then a | be for all integers c;
iii) If a | b and b |c, then a | c.
Transcribed Image Text:5. In Problem 5 use the definition of divisibility to do a direct proof of the theorem. Definition. If a and b are integers with a + 0, we say that a divides b if there is an integer e such that b = ac. When a divides b we say that a is a factor or divisor of b, and b is a multiple of a. The notation alb denotes that a divides b. We write a { b when a does not divide b. Theorem. Let a, b and e be integers, where a + 0. Then i) If a | b and a c, then a | (b+c); ii) If a | b, then a | be for all integers c; iii) If a | b and b |c, then a | c.
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