5. Imagine you can distribute a total charge of Q unto two objects separated by distance r so that there is an electric force between them. You place a charge of q, on the first and q, on the second with q,+q,=Q. The amount of force between the objects will depend on how much of Q you put on each object, how it is divided it up. For example, if you put it all of Q on the first object, q=Q & q2=0, the force between the objects is zero! 5.1. Show that to maximize this force, you should place half of the total charge, Q/2, on each. This problem is a bit tricky so l'll step you through some of it. 5.1.1.Write q, in terms of qz and Q and then plug your expression into Coulomb's Law. 5.1.2.Now, to find the value of g2 that maximizes F, take the derivative of F with respect to q2, dF/dq2, and set it equal to zero (remember this process?) 5.1.3.Solve this for the maximum value of q, in terms of the total charge.

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5. Imagine you can distribute a total charge of Q unto two objects separated by distance r so that there is an electric
force between them. You place a charge of q, on the first and q, on the second with q,+q2=Q. The amount of force
between the objects will depend on how much of Q you put on each object, how it is divided it up. For example, if
you put it all of Q on the first object, q=Q & q2=0, the force between the objects is zero!
5.1. Show that to maximize this force, you should place half of the total charge, Q/2, on each. This problem is a bit
tricky so l'll step you through some of it.
5.1.1.Write qı in terms of q2 and Q and then plug your expression into Coulomb's Law.
5.1.2.Now, to find the value of q2 that maximizes F, take the derivative of F with respect to q2, dF/dq2, and set it
equal to zero (remember this process?)
5.1.3.Solve this for the maximum value of q2 in terms of the total charge.
Transcribed Image Text:Page 5. Imagine you can distribute a total charge of Q unto two objects separated by distance r so that there is an electric force between them. You place a charge of q, on the first and q, on the second with q,+q2=Q. The amount of force between the objects will depend on how much of Q you put on each object, how it is divided it up. For example, if you put it all of Q on the first object, q=Q & q2=0, the force between the objects is zero! 5.1. Show that to maximize this force, you should place half of the total charge, Q/2, on each. This problem is a bit tricky so l'll step you through some of it. 5.1.1.Write qı in terms of q2 and Q and then plug your expression into Coulomb's Law. 5.1.2.Now, to find the value of q2 that maximizes F, take the derivative of F with respect to q2, dF/dq2, and set it equal to zero (remember this process?) 5.1.3.Solve this for the maximum value of q2 in terms of the total charge.
Expert Solution
Step 1

Given

a charge Q that can be distributed into two sub charges q1 and q2 therefore

q1+q2=Q

or

q1=Q-q2...(i)

 

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