5. If 90° < 0 < 180° and cos 0 = — 1, find cos 20. ㅇ 곯 ○ 16 25 0-곯 ㅇ

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Trigonometry Problem: Finding cos 2θ

**Problem Statement:**
Given that \(90^\circ < \theta < 180^\circ\) and \(\cos \theta = -\frac{3}{5}\), find \(\cos 2\theta\).

**Multiple Choice Answers:**
- A) \(\frac{7}{25}\)
- B) \(-\frac{16}{25}\)
- C) \(-\frac{7}{25}\)
- D) \(\frac{16}{25}\)

**Explanation:**
To find \(\cos 2\theta\), you can use the double-angle identity for cosine:
\[
\cos 2\theta = 2\cos^2 \theta - 1
\]
First, calculate \( \cos^2 \theta \):
\[
\cos \theta = -\frac{3}{5}
\]
\[
\cos^2 \theta = \left(-\frac{3}{5}\right)^2 = \frac{9}{25}
\]

Next, apply the value to the double-angle formula:
\[
\cos 2\theta = 2\left(\frac{9}{25}\right) - 1 = \frac{18}{25} - 1 = \frac{18}{25} - \frac{25}{25} = -\frac{7}{25}
\]

Thus, the correct answer is:
- C) \(-\frac{7}{25}\)
Transcribed Image Text:### Trigonometry Problem: Finding cos 2θ **Problem Statement:** Given that \(90^\circ < \theta < 180^\circ\) and \(\cos \theta = -\frac{3}{5}\), find \(\cos 2\theta\). **Multiple Choice Answers:** - A) \(\frac{7}{25}\) - B) \(-\frac{16}{25}\) - C) \(-\frac{7}{25}\) - D) \(\frac{16}{25}\) **Explanation:** To find \(\cos 2\theta\), you can use the double-angle identity for cosine: \[ \cos 2\theta = 2\cos^2 \theta - 1 \] First, calculate \( \cos^2 \theta \): \[ \cos \theta = -\frac{3}{5} \] \[ \cos^2 \theta = \left(-\frac{3}{5}\right)^2 = \frac{9}{25} \] Next, apply the value to the double-angle formula: \[ \cos 2\theta = 2\left(\frac{9}{25}\right) - 1 = \frac{18}{25} - 1 = \frac{18}{25} - \frac{25}{25} = -\frac{7}{25} \] Thus, the correct answer is: - C) \(-\frac{7}{25}\)
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