**Question:**If 800 micrograms (ug) of arsenic-76 are present in an artifact, how much arsenic-76 will be present after 132.5 hours? The half-life of arsenic-76 is 26.5 hours. \[SHOW WORK\]**Explanation:**To answer this question, we'll use the concept of radioactive decay and half-life. The half-life is the time required for half of the radioactive substance to decay.Here are the steps to solve the problem:1. **Determine the number of half-lives:** The number of half-lives (\(n\)) that have passed can be calculated using the formula: \[ n = \frac{\text{total time}}{\text{half-life}} \] Given: - Total time (\(t\)) = 132.5 hours - Half-life (\(t_{1/2}\)) = 26.5 hours \[ n = \frac{132.5}{26.5} \approx 5 \]2. **Calculate the remaining amount of arsenic-76:** After each half-life, the amount of radioactive substance decreases by half. So, the remaining amount can be calculated using the formula: \[ \text{Remaining amount} = \text{initial amount} \times \left( \frac{1}{2} \right)^n \] Given: - Initial amount = 800 micrograms - Number of half-lives (\(n\)) = 5 \[ \text{Remaining amount} = 800 \times \left( \frac{1}{2} \right)^5 \] \[ \text{Remaining amount} = 800 \times \frac{1}{32} = 25 \text{ micrograms} \]Therefore, 25 micrograms of arsenic-76 will be present after 132.5 hours.

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Answered: 5. If 800-ug of arsenic-76 are present…

5. If 800-ug of arsenic-76 are present in an artifact, how much arsenic-76 will be present after 132.5 hours? [SHOW WORK] The half-life of arsenic-76 is 26.5 hours.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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