5. How fast would a 61 kg person have to run (in m/s) in order to have same energy as that of a 110 w light bulb uses per hour. Ans: 113.9 →KE=mv/ Light bulb Power %3D Energy->KE, Person Power, P- E Energy t. t time Eneray, E= P.t A95kg hall movzing at 245 m/a ono borizoatal Cin poving ot 24 im/a onn borigental Ci

5. How fast would a 61 kg person have to run (in m/s) in order to have same energy as that of a 110 w light bulb uses per hour. Ans: 113.9 →KE=mv/ Light bulb Power %3D Energy->KE, Person Power, P- E Energy t. t time Eneray, E= P.t A95kg hall movzing at 245 m/a ono borizoatal Cin poving ot 24 im/a onn borigental Ci

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter7: Work, Energy, And Energy Resources

Section: Chapter Questions

Problem 10PE: (a) How fast must a 3000-kg elephant move to have the same kinetic energy as a 65.0-kg sprinter...

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