5. How fast would a 61 kg person have to run (in m/s) in order to have same energy as that of a 110 w light bulb uses per hour. Ans: 113.9 →KE=mv/ Light bulb Power %3D Energy->KE, Person Power, P- E Energy t. t time Eneray, E= P.t A95kg hall movzing at 245 m/a ono borizoatal Cin poving ot 24 im/a onn borigental Ci

5. How fast would a 61 kg person have to run (in m/s) in order to have same energy as that of a 110 w light bulb uses per hour. Ans: 113.9 →KE=mv/ Light bulb Power %3D Energy->KE, Person Power, P- E Energy t. t time Eneray, E= P.t A95kg hall movzing at 245 m/a ono borizoatal Cin poving ot 24 im/a onn borigental Ci

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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