5. Given the bases B and C, and the given vector in one the bases, find the coordinate vector in the other basis. a. B= [*]c 10 2 b. B= -3 10

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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5. Given the bases B and C, and the given vector in one of the bases, find the coordinate vector in the other basis.

a. 

- Basis \(\mathscr{B}\): \(\left\{ \begin{bmatrix} 1 \\ 2 \\ 4 \end{bmatrix}, \begin{bmatrix} 2 \\ 1 \\ 3 \end{bmatrix}, \begin{bmatrix} 2 \\ 2 \\ 1 \end{bmatrix} \right\}\)

- Basis \(\mathscr{C}\): \(\left\{ \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix}, \begin{bmatrix} 0 \\ 1 \\ 1 \end{bmatrix}, \begin{bmatrix} 3 \\ 4 \\ 5 \end{bmatrix} \right\}\)

- Coordinate vector in basis C: \([\mathbf{x}]_C = \begin{bmatrix} -4 \\ 10 \\ 11 \end{bmatrix}_C\)

b.

- Basis \(\mathscr{B}\): \(\left\{ \begin{bmatrix} 1 \\ -2 \\ 2 \end{bmatrix}, \begin{bmatrix} 5 \\ 1 \\ 2 \end{bmatrix}, \begin{bmatrix} 0 \\ 0 \\ 1 \end{bmatrix} \right\}\)

- Basis \(\mathscr{C}\): \(\left\{ \begin{bmatrix} 2 \\ 0 \\ 3 \end{bmatrix}, \begin{bmatrix} 1 \\ 1 \\ -1 \end{bmatrix}, \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} \right\}\)

- Coordinate vector in basis B: \([\mathbf{x}]_B = \begin{bmatrix} 5 \\ 2 \\ -3 \\ 10 \end{bmatrix}_B\)
Transcribed Image Text:5. Given the bases B and C, and the given vector in one of the bases, find the coordinate vector in the other basis. a. - Basis \(\mathscr{B}\): \(\left\{ \begin{bmatrix} 1 \\ 2 \\ 4 \end{bmatrix}, \begin{bmatrix} 2 \\ 1 \\ 3 \end{bmatrix}, \begin{bmatrix} 2 \\ 2 \\ 1 \end{bmatrix} \right\}\) - Basis \(\mathscr{C}\): \(\left\{ \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix}, \begin{bmatrix} 0 \\ 1 \\ 1 \end{bmatrix}, \begin{bmatrix} 3 \\ 4 \\ 5 \end{bmatrix} \right\}\) - Coordinate vector in basis C: \([\mathbf{x}]_C = \begin{bmatrix} -4 \\ 10 \\ 11 \end{bmatrix}_C\) b. - Basis \(\mathscr{B}\): \(\left\{ \begin{bmatrix} 1 \\ -2 \\ 2 \end{bmatrix}, \begin{bmatrix} 5 \\ 1 \\ 2 \end{bmatrix}, \begin{bmatrix} 0 \\ 0 \\ 1 \end{bmatrix} \right\}\) - Basis \(\mathscr{C}\): \(\left\{ \begin{bmatrix} 2 \\ 0 \\ 3 \end{bmatrix}, \begin{bmatrix} 1 \\ 1 \\ -1 \end{bmatrix}, \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} \right\}\) - Coordinate vector in basis B: \([\mathbf{x}]_B = \begin{bmatrix} 5 \\ 2 \\ -3 \\ 10 \end{bmatrix}_B\)
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