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5. From the following heats of reaction at 25C, H2 (8) S (s) + 2 O2 (8) = H2SO4 (1) Na (s)t ½ Cl2 (g) = NaCl (s) H = -881.32 KJ H -411 KJ wWww ½ Halg) + % Cl2 (g) = HCI (g) H = -92.3 KJ %3D 2 Na (s).+ S (s) + 2 02 (g) = Na2SO4 (s) H = -1,382.8 KJ calculate the heat of reaction at constant volume at 25C for the process: 2NACI (s)+ H2SO4 (1) = NazSO4 (s) + 2 HCI (g)

5. From the following heats of reaction at 25C, H2 (8) S (s) + 2 O2 (8) = H2SO4 (1) Na (s)t ½ Cl2 (g) = NaCl (s) H = -881.32 KJ H -411 KJ wWww ½ Halg) + % Cl2 (g) = HCI (g) H = -92.3 KJ %3D 2 Na (s).+ S (s) + 2 02 (g) = Na2SO4 (s) H = -1,382.8 KJ calculate the heat of reaction at constant volume at 25C for the process: 2NACI (s)+ H2SO4 (1) = NazSO4 (s) + 2 HCI (g)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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5. From the following heats of reaction at 25C, H2 (g)+ S (s) + 2 02 (g) = H2SO4 (1) Na (s) + ½ Cl2 (g) = NaCl (s) ½ H2(g) + ½ Cl2 (g) = HCI (g) 2 Na (s) + S (s) + 2 02 (g) = NazSO4 (s) H = -881.32 KJ H = -411 KJ www H = -92.3 KJ w H -1,382.8 KJ %3D calculate the heat of reaction at constant volume at 25C for the process: 2NacI (s) + H2SO4 (1) = NazsO4 (s) + 2 HCI (g)
Transcribed Image Text:5. From the following heats of reaction at 25C, H2 (g)+ S (s) + 2 02 (g) = H2SO4 (1) Na (s) + ½ Cl2 (g) = NaCl (s) ½ H2(g) + ½ Cl2 (g) = HCI (g) 2 Na (s) + S (s) + 2 02 (g) = NazSO4 (s) H = -881.32 KJ H = -411 KJ www H = -92.3 KJ w H -1,382.8 KJ %3D calculate the heat of reaction at constant volume at 25C for the process: 2NacI (s) + H2SO4 (1) = NazsO4 (s) + 2 HCI (g)
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