I understand the steps for the mean and variance. However, for the variance, I wonder if there's an easier way to obtain the answer. I attached the question and my work for mean and variance. As for the area & median, I'm stuck. meen.A2BH=/2Cw)(n) = 10.2-0.02 x15hergntSlopevariunce02y2 0.015nearx 10.2-0.02x)d水: るmean= 8.33)(0.2-0.02x)(v= -2xutu2)(U.2-0.02 x)dx,L0.2x2 -0.02y3-04xん+0.04x2ん+0.2ん-9.02x ldx0,2 - 0.02"-0.43u r0.04u t. Zuzx -0z x2u2 5.Finding means, variances, medians.For the following probability density function, fx(x), of a random variable X, integrate itto find the equation for the cumulative distribution function, Fx(x), (ranging from 0 to 1),and the median, mean and variance of the distribution. Finally, compute the area underthe probability of exceedance function, 1- Fx(x).Show how to get median of 7.93, mean of 8.33, variance of 5.55. and area of 8.33.fx(x)1015

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Answered: 5. Finding means, variances, medians.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I understand the steps for the mean and variance. However, for the variance, I wonder if there's an easier way to obtain the answer. I attached the question and my work for mean and variance.

As for the area & median, I'm stuck.

meen.
A2BH=/2Cw)(n) = 1
0.2-0.02 x
15
hergnt
Slope
variunce
02y2 0.0
15
near
x 10.2-0.02x)d水: る
mean= 8.33
)(0.2-0.02x)
(v= -2xutu2)(U.2-0.02 x)dx
,L
0.2x2 -0.02y3-04xん+0.04x2ん+0.2ん-9.02x ldx
0,2 - 0.02"-0.43u r0.04u t. Zuzx -0z x2u2

5.
Finding means, variances, medians.
For the following probability density function, fx(x), of a random variable X, integrate it
to find the equation for the cumulative distribution function, Fx(x), (ranging from 0 to 1),
and the median, mean and variance of the distribution. Finally, compute the area under
the probability of exceedance function, 1- Fx(x).
Show how to get median of 7.93, mean of 8.33, variance of 5.55. and area of 8.33.
fx(x)
10
15

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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