5. Find the order of growth for solutions of the following recurrences. a. T(n)=4T (n/2) +n, T(1) = 1 b. T(n)= 4T (n/2) + n², T (1) = 1 c. T(n)= 4T (n/2) + n³, T (1) = 1 %3D %3D %3D
5. Find the order of growth for solutions of the following recurrences. a. T(n)=4T (n/2) +n, T(1) = 1 b. T(n)= 4T (n/2) + n², T (1) = 1 c. T(n)= 4T (n/2) + n³, T (1) = 1 %3D %3D %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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#5
Expert Solution
Step 1
5(a) We have
Given T(1) = 1
1 =
4T(1/2) = 0
T(1/2) = 0
Here n has the largest growth rate in T(n)
The order of growth for T(n) = 4T(n/2) +n is O(n)
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