5. Find the coordinates of the points on the cross sectional curve of the intersection of the cone z = √x² + y² and the plane x + 2y + 3z = 3 that have maximum and minimum distance from the xy-plane (see the sketch below). Hint: Use the Lagrange Multipliers method. cone intersection curve plane xy-plane

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Q: Use the Law of Sines to solve the triangle. (If an answer does not exist, enter DNE. Round your…

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Q: Q3: Find the distance between the origin and the plane containing the points A(1,1,0), B(-1,0,1) and…

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Q: 5. Find the coordinates of the points on the cross sectional curve of the intersection of the cone 2…

A: Given equation of cone and plane is  z=x2+y2⇒fx,y,z=z2-x2-y2…

Q: Use LaGrange multipliers to find the points on the surface 2² = x² + y² which are closest to (4, 2,…

A: Given surface z2=x2+y2 and the point (4,2,0). The objective is to find the points on the surface…

Q: Find the point at which the line r(t) = (7, −7, 4) + t(−6, 6, −8) intersects the az plane.…

A: To find the point where the line intersects xz plane

Q: 1. Find the distance from the point S(2,-3,4) to the plane x+ 2y+ 2z = 13 2. Find the distance from…

A:

Q: Let L be a line which passes through the point (-8, 0, 1) and is perpendicular to the plane a + 2y +…

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Q: Find the distance the point P(2,0,1) is form the plane 3x – 6y + 2z = 15. -

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Q: 3. Use LaGrange multipliers to find the point on the plane 2r - y+4z = 10 that is closest to the…

A: Use Lagrange method to find point

Q: d the distance between the point (2, -4, 3) and the plane 5x – 2y + z = 10

A: