5. Find an equation for the graph: 1- A) y = 2 cos(3Tx) B) y = 3 cos s(x) C) y = 3 cos(2nx) D) y = 2 cos

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 59E
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**Problem 5: Find an Equation for the Graph**

The task is to determine the correct equation represented by the given graph. 

### Details of the Graph:

- The graph displays a trigonometric function, specifically a cosine function, as evidenced by its wave-like pattern.
- The graph oscillates between \( y = 2 \) and \( y = -2 \), indicating that the amplitude of the function is 2.
- The graph completes a full cycle over an interval of 2 on the x-axis. This means the period of the function is 2.

### Potential Equations:

A) \( y = 2 \cos(3\pi x) \)

B) \( y = 3 \cos\left(\frac{\pi}{2} x\right) \)

C) \( y = 3 \cos(2\pi x) \)

D) \( y = 2 \cos\left(\frac{\pi}{3} x\right) \)

### Analysis:

To match the graph to one of the equations, we compare their characteristics:

1. **Amplitude:**
   - The amplitude of the graph is 2.
   - Therefore, the equations must have an amplitude of 2.

   This eliminates options B and C, as their amplitudes are 3.

2. **Period:**
   - For a cosine function \( y = A \cos(Bx) \), the period \( P \) is found using \( P = \frac{2\pi}{B} \).
   - The graph's period is 2.

   Let's compute the period for the remaining equations:
   - For \( y = 2 \cos(3\pi x) \):
     \[
     P = \frac{2\pi}{3\pi} = \frac{2}{3}
     \]
   - For \( y = 2 \cos\left(\frac{\pi}{3} x\right) \):
     \[
     P = \frac{2\pi}{\frac{\pi}{3}} = 6
     \]

Neither option has the correct period of 2.

#### Correct Equation:

Considering these analyses, it appears there is an error in the period calculations. Since none of the options directly provide a period of 2 with an amplitude of 2, none of the given equations perfectly matches the graph. However, in a close approximation, the period
Transcribed Image Text:**Problem 5: Find an Equation for the Graph** The task is to determine the correct equation represented by the given graph. ### Details of the Graph: - The graph displays a trigonometric function, specifically a cosine function, as evidenced by its wave-like pattern. - The graph oscillates between \( y = 2 \) and \( y = -2 \), indicating that the amplitude of the function is 2. - The graph completes a full cycle over an interval of 2 on the x-axis. This means the period of the function is 2. ### Potential Equations: A) \( y = 2 \cos(3\pi x) \) B) \( y = 3 \cos\left(\frac{\pi}{2} x\right) \) C) \( y = 3 \cos(2\pi x) \) D) \( y = 2 \cos\left(\frac{\pi}{3} x\right) \) ### Analysis: To match the graph to one of the equations, we compare their characteristics: 1. **Amplitude:** - The amplitude of the graph is 2. - Therefore, the equations must have an amplitude of 2. This eliminates options B and C, as their amplitudes are 3. 2. **Period:** - For a cosine function \( y = A \cos(Bx) \), the period \( P \) is found using \( P = \frac{2\pi}{B} \). - The graph's period is 2. Let's compute the period for the remaining equations: - For \( y = 2 \cos(3\pi x) \): \[ P = \frac{2\pi}{3\pi} = \frac{2}{3} \] - For \( y = 2 \cos\left(\frac{\pi}{3} x\right) \): \[ P = \frac{2\pi}{\frac{\pi}{3}} = 6 \] Neither option has the correct period of 2. #### Correct Equation: Considering these analyses, it appears there is an error in the period calculations. Since none of the options directly provide a period of 2 with an amplitude of 2, none of the given equations perfectly matches the graph. However, in a close approximation, the period
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