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5. Evaluate the integral using the following: . Formulas: a. [²x²³ dx = 4/7/ [²³x³dx x³ dx b. L'a (12x3 +24x² - 8x) dx Cdx = C(b-a) C dx = C(b-a) (C any constant)

5. Evaluate the integral using the following: . Formulas: a. [²x²³ dx = 4/7/ [²³x³dx x³ dx b. L'a (12x3 +24x² - 8x) dx Cdx = C(b-a) C dx = C(b-a) (C any constant)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**5. Evaluate the integral using the following:** - **Formulas:** - \(\int_{0}^{b} x^3 \, dx = \frac{b^4}{4}\) - \(\int_{a}^{b} C \, dx = C(b-a)\) (C any constant) - \(\int_{0}^{b} x \, dx = \frac{1}{2}b^2\) - \(\int_{0}^{b} x^2 \, dx = \frac{1}{3}b^3\) a. \(\int_{0}^{3} x^3 \, dx\) b. \(\int_{0}^{1} (12x^3 + 24x^2 - 8x) \, dx\)
Transcribed Image Text:**5. Evaluate the integral using the following:** - **Formulas:** - \(\int_{0}^{b} x^3 \, dx = \frac{b^4}{4}\) - \(\int_{a}^{b} C \, dx = C(b-a)\) (C any constant) - \(\int_{0}^{b} x \, dx = \frac{1}{2}b^2\) - \(\int_{0}^{b} x^2 \, dx = \frac{1}{3}b^3\) a. \(\int_{0}^{3} x^3 \, dx\) b. \(\int_{0}^{1} (12x^3 + 24x^2 - 8x) \, dx\)
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