5. Determine Art for the decomposition of hydrogen peroxide. H₂O₂(1)→O₂(g)+ H₂O(1) Given: H₂(g) + O₂(g) H₂O₂(1) H₂(9) + O₂(g) →H₂O(1) B) #93.89 kJ/mol A) -98.05 kJ/mol ArH=-187.78 KJ/mol ArH=-285.83 kJ/mol C) -191.94 kJ/mol 30 D)-93.89 kJ/mol 6. For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy? B) 2p -> 6d C) 6p 4s D) 7f-5d
5. Determine Art for the decomposition of hydrogen peroxide. H₂O₂(1)→O₂(g)+ H₂O(1) Given: H₂(g) + O₂(g) H₂O₂(1) H₂(9) + O₂(g) →H₂O(1) B) #93.89 kJ/mol A) -98.05 kJ/mol ArH=-187.78 KJ/mol ArH=-285.83 kJ/mol C) -191.94 kJ/mol 30 D)-93.89 kJ/mol 6. For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy? B) 2p -> 6d C) 6p 4s D) 7f-5d
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Transcribed Image Text:+)
w many photons of light with frequency 5.50 x 10¹5 Hz are required to provide 1 kJ of energy?
364 x 10-18
B) 2.74 x 1020
C) 4.56 x 104
D) 1.65 x 104
2. What is the wavelength of a bullet that is 0.450 g traveling at 2000. m/s?
A) 2000 m
(B) 294 x 10-24 m
C) 7.36 x 10-4 m
4. What is the total number of orbitals possible with n = 3?
(A) 9
(B) 16
3. How many electrons in a bromine atom have an angular momentum quantum number, , equal to 0?
4) 2
B) 8
C) 7
D) 17
A) -98.05 kJ/mol
C) 32
5. Determine ArH® for the decomposition of hydrogen peroxide. H₂O₂(1)→O₂(g) + H₂O(1)
Given: H₂(g) + O₂(g) → H₂O₂(1)
H₂(g) + O2(g) → H₂O(1)
B)93.89 kJ/mol
ArH=-187.78 kJ/mol
ArH=-285.83 kJ/mol
C) -191.94 kJ/mol
D) 7.36 x 107 m
E) 3.64 x 10-16
8. Identify the type of orbital that has five radial nodes and zero angular nodes?
A) 4d
B) 5s
C) 5p
A) Pauli Exclusion Principle
C) The DeBroglie Relationship
D) 3
6. For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest
energy?
(A)2s - 3p
B) 2p → 6d
C) 6p+ 4s
D) 7f-5d
7. The possible value(s) of the orbital angular momentum quantum number of a 3p electron are:
B) -1, 0, +1
A)+1/2, -1/2
C) 0
(D) 1
D)-93.89 kJ/mol
D6s
9. If 4.800 x 10-5 mol of uranium-238 at 4500 K effuses through a hole in 125 seconds, how many mol of
C) 4.80 x 10-5 mol
uranium-235 will effuse through the same hole, at the same temperature and in the same amount of time?
B) 4.77 x 10-5 mol
A) 4.74 x 10-5 mol
D) 4.86 x 10-5 mol
(E) 4.83 x 10-5 mol
B) Hund's Rule
E) Heisenberg Uncertainty Principle
10. The fact that we cannot simultaneously measure the exact position and precise momentum of an elect
is referred to as:
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