5.2.4.1.3.a. 0.008 651 g2005.040 x 10-4 mc. 740 000 LялIf a 6.00% (w/v) citric acid solution contains 6.00 grams of citric acid in every 100.0 mL of thesolution, how many grams of citric acid are present in 495 mL of the 6.00% (w/v) solution? Showyour work using dimensional analysis and report your answer with the correct number of significantfigures.495x6.00g citric acid.100ml sol29.7citric acicogWhat volume of the 6.00% (w/v) citric acid solution described above would be needed to provide565 mg of citric acid for a reaction? For full credit, show your work using a single dimensionalanalysis grid (or one chain of conversion factors) and report your answer with the correct number ofsignificant figures. (You should know the relationship between grams and milligrams.)5651006.009X.Convert 0.000 083 20 to scientific notation (without rounding).8.32 х 10-56.06100LIMA1000wwHg-0.0941g citric acid7.08mLConvert 68.0 ft/s to km/h using dimensional analysis. For full credit, use one long chain ofconversion factors using the given relationships below plus relationships between meters andcentimeters and between meters and kilometers (relationships you should know). Report youranswer with the correct number of significant figures.Given: 1 ft = 12 in, 1 in = 2.54 cm, 60 min = 1 h, 60 s = 1 min3410 10103

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5. Convert 68.0 ft/s to km/h using dimensional analysis. For full credit, use one long chain of conversion factors using the given relationships below plus relationships between meters and centimeters and between meters and kilometers (relationships you should know). Report your answer with the correct number of significant figures. Given: 1 ft = 12 in, 1 in = 2.54 cm, 60 min = 1 h, 60 s = 1 min

5. Convert 68.0 ft/s to km/h using dimensional analysis. For full credit, use one long chain of conversion factors using the given relationships below plus relationships between meters and centimeters and between meters and kilometers (relationships you should know). Report your answer with the correct number of significant figures. Given: 1 ft = 12 in, 1 in = 2.54 cm, 60 min = 1 h, 60 s = 1 min

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Using the table of equalities, calculate the number of cups in 1.0 gallons (gal). Remember to select an answer with the correct number of significant figures. Some Common Equalities Quantity Metric (SI) Length Volume Mass Time 1000 m 1 km Im= 1000 mm 1 cm 10 mm IL 1000 mL 1 dl = 100 mL 1 mL = 1 cm³ 1 kg = 1000 g 1 g = 1000 mg 1 h = 60 min 1 min = 60 s U.S. 1 ft = 12 in. 1 yd = 3 ft 1 mi 5280 ft 1 qt = 4 cups 1 qt=2pt 1 gal - 4 qt 1 lb = 16 oz 1 h = 60 min 1 min = 60 s Metric-U.S. 2.54 cm 1 in. (exact) I m = 39.4 in. 1 km 0.621 mi 946 mL- 1 qt 1L = 1.06 qt 1 kg = 2.20 lb 454 g 1 lb 12 cups 16 cups 64 cups 8.0 cups I DON'T KNOW YET
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A nickel is found to have a mass of 4.87 grams. Using unit analysis, show what the mass of this nickel is in pounds. Use one of the following to set up the conversion factor. 454 g = 1 lb = 16 oz 1 m = 39.4 in= 3.28 feet 1 km = 0.621 mile 1 L = 1.06 qt 2.54 cm = 1 in 3.79 L=1 gal 4.87 grams X (number) 459 (number) lb Use the References to access important values if needed f g (unit) (unit) lb