5. Consider the following Java statements: int n = 4; StackInterface stack = new MyStack( ); while (n > 0) { stack.push(n): n--; }// end while int result = 1; while (Istack.isEmpty()) { int integer = myStack.pop(): result = result * integer; }// end while System.out.printIn("result = " + result); a. What value is displayed when this code executes? b. What mathematical function does the code evaluate?
5. Consider the following Java statements: int n = 4; StackInterface stack = new MyStack( ); while (n > 0) { stack.push(n): n--; }// end while int result = 1; while (Istack.isEmpty()) { int integer = myStack.pop(): result = result * integer; }// end while System.out.printIn("result = " + result); a. What value is displayed when this code executes? b. What mathematical function does the code evaluate?
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:The image presents a Java code snippet for evaluating a mathematical function using stack operations.
### Java Code Explanation:
```java
int n = 4;
StackInterface<Integer> stack = new MyStack<Integer>();
while (n > 0) {
stack.push(n);
n--;
} // end while
int result = 1;
while (!stack.isEmpty()) {
int integer = myStack.pop();
result = result * integer;
} // end while
System.out.println("result = " + result);
```
#### Explanation:
- The code initializes an integer `n` with the value `4`.
- A stack (`stack`) is created using the `StackInterface` and `MyStack` classes.
- The first `while` loop pushes the values `4, 3, 2, 1` onto the stack, decrementing `n` in each iteration until `n` becomes `0`.
- After the loop, the stack contains the integers 4, 3, 2, and 1, in that order.
- The variable `result` is initialized to `1`.
- The second `while` loop iterates as long as the stack is not empty. In each iteration, it pops the top integer from the stack and multiplies `result` by this integer.
- Finally, the program prints the `result`, which is the product of all integers initially pushed onto the stack.
### Questions:
a. **What value is displayed when this code executes?**
- The value displayed is `24`. This is the factorial of `4` (i.e., `4! = 4 * 3 * 2 * 1 = 24`).
b. **What mathematical function does the code evaluate?**
- The code evaluates the factorial of `n`, where `n = 4`.
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