5. Calculate wavenumber for C=C and C=C by Hook's law. stronger bond higher frequency --- f = force constant m = mass k = constant Hooke's law V = k/ smaller mass --→ higher frequency The force constant (f) of C=C 10 x 105 dyne/cm and C=C, 15 x 105 dyne/cm The mass (m) is the mass of atoms (or weights). The smaller the value of m, the higher the V of vibration. CH30. HO capsaicin (spicy component of hot peppers)
5. Calculate wavenumber for C=C and C=C by Hook's law. stronger bond higher frequency --- f = force constant m = mass k = constant Hooke's law V = k/ smaller mass --→ higher frequency The force constant (f) of C=C 10 x 105 dyne/cm and C=C, 15 x 105 dyne/cm The mass (m) is the mass of atoms (or weights). The smaller the value of m, the higher the V of vibration. CH30. HO capsaicin (spicy component of hot peppers)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![## Understanding Wavenumber Calculation Using Hooke's Law
### Problem Statement
5. Calculate the wavenumber for C=C and C≡C using Hooke's law.
### Hooke's Law
Hooke's Law for vibration frequency is given by the formula:
\[
\tilde{\nu} = k \sqrt{\frac{f}{m}}
\]
- \( \tilde{\nu} \): wavenumber
- \( f \): force constant
- \( m \): mass
- \( k \): constant
**Principles:**
- **Stronger Bond ➔ Higher Frequency**
- **Smaller Mass ➔ Higher Frequency**
### Force Constants
- **C=C (Double Bond):** \( f = 10 \times 10^5 \, \text{dyne/cm} \)
- **C≡C (Triple Bond):** \( f = 15 \times 10^5 \, \text{dyne/cm} \)
The mass (\( m \)) is the mass of atoms (or weights). The smaller the value of \( m \), the higher the wavenumber (\( \tilde{\nu} \)) of vibration.
### Structure of Capsaicin
Below the explanation, the chemical structure of capsaicin, a spicy component found in hot peppers, is provided.

- **Key Structural Details:**
- CH₃O (methoxy group)
- HO (hydroxy group)
- N-H (amide group)
- Various hydrocarbon chains and rings
Understanding the vibration principles and structural details of molecules helps in studying their chemical behavior and interactions efficiently.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca7515a8-b44b-40fa-83f2-449e6ef6ad98%2Fb3afef1a-2087-4009-a0f3-251294e96b97%2Ff46l5n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Understanding Wavenumber Calculation Using Hooke's Law
### Problem Statement
5. Calculate the wavenumber for C=C and C≡C using Hooke's law.
### Hooke's Law
Hooke's Law for vibration frequency is given by the formula:
\[
\tilde{\nu} = k \sqrt{\frac{f}{m}}
\]
- \( \tilde{\nu} \): wavenumber
- \( f \): force constant
- \( m \): mass
- \( k \): constant
**Principles:**
- **Stronger Bond ➔ Higher Frequency**
- **Smaller Mass ➔ Higher Frequency**
### Force Constants
- **C=C (Double Bond):** \( f = 10 \times 10^5 \, \text{dyne/cm} \)
- **C≡C (Triple Bond):** \( f = 15 \times 10^5 \, \text{dyne/cm} \)
The mass (\( m \)) is the mass of atoms (or weights). The smaller the value of \( m \), the higher the wavenumber (\( \tilde{\nu} \)) of vibration.
### Structure of Capsaicin
Below the explanation, the chemical structure of capsaicin, a spicy component found in hot peppers, is provided.

- **Key Structural Details:**
- CH₃O (methoxy group)
- HO (hydroxy group)
- N-H (amide group)
- Various hydrocarbon chains and rings
Understanding the vibration principles and structural details of molecules helps in studying their chemical behavior and interactions efficiently.
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