5. Calculate the work for the expansion of 3 moles of B,H at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for äntermolecular forces (a) is 6.048 bar L'/mol' and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: + a - RT A. 2352.2376 J C. 2118.1071 J B. -2352.2376 J D. -2118.1071 J
5. Calculate the work for the expansion of 3 moles of B,H at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for äntermolecular forces (a) is 6.048 bar L'/mol' and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: + a - RT A. 2352.2376 J C. 2118.1071 J B. -2352.2376 J D. -2118.1071 J
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![5. Calculate the work for the expansion of 3 moles of B;Hs at 40"C from 2.74 L to 3.89 L using van der Waals equation. The
correction for intermolecular forces (a) is 6.048 bar L?/mol and the adjustment factor of the volume (b) is 0.07437 L/mol.
The general equation for van der Waals is written below:
+ a
=.
A. 2352.2376J
B. -2352.2376 J
C. 2118.1071J
D. -2118.1071 J](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4153ced8-7060-440a-aa0f-7101d2651cb5%2F9bded7d6-9ba6-4e28-ba60-85be47566c34%2Fvii5nx_processed.png&w=3840&q=75)
Transcribed Image Text:5. Calculate the work for the expansion of 3 moles of B;Hs at 40"C from 2.74 L to 3.89 L using van der Waals equation. The
correction for intermolecular forces (a) is 6.048 bar L?/mol and the adjustment factor of the volume (b) is 0.07437 L/mol.
The general equation for van der Waals is written below:
+ a
=.
A. 2352.2376J
B. -2352.2376 J
C. 2118.1071J
D. -2118.1071 J
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