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5. Calculate the percent error between the value of AH for reaction 2 and the sum of AH for reaction 1 plus AH for reaction 3. (Assume AH for reaction 2 to be the accepted value). Show your work. Account for any similarity or difference.

5. Calculate the percent error between the value of AH for reaction 2 and the sum of AH for reaction 1 plus AH for reaction 3. (Assume AH for reaction 2 to be the accepted value). Show your work. Account for any similarity or difference.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. Write net ionic equations for Reactions 1, 2 and 3. Consider the heat given off in your reactions; include the heat evolved in kJ/mole for each reaction. Reaction1: Heat of NaOH solution (solid NaOH + H2O) NaOH(s) > Na(ag) + OH (aa) Molar mass of NaOH: 39.998 g/mol mass NaOH п (Na0H) 3D M NaOH 1.0 g п (NaOH) = 0.025 mol 39.998 g/mol 1.129 kJ ΔΗ - -= - 45.16 kJ /mol 0.025 mol Reaction 2: Heat of NaOH solution (solid NaOH + HCI solution) NaOH(s) + HCl(ag) → H2Oa) + NaClao) mass NaOH п (NaOH) %3D M NaOH 1.0 g п (Na0H) = 0.025 mol 39.998 g/mol - 2.5 k) ΔΗ 100.0 kJ/mol 25: Reaction 3: Heat of Neutralization (NaOH solution + HCI solution) NaOH(ag) + HCl(ag) → H200 + NaCl(ag) mass NaOH п (NaOH) 3D M NaOH 1.0 g п (Na0H) %3 = 0.025 mol 39.998 g/mol -1.400 kJ ΔΗ- -56 kJ /mol 0.025 mol pg. 7 3. The energy in Reaction 1 represents the energy of solution for one mole of NaOH (s). Look at the net ionic equations for Reactions 2 and 3, and make a similar statement concerning the significance of AH for reactions 2 and 3. Enthalpy change of reaction 2 represents the heat evolved as the hydrogen ion displaces the sodium ion, creating a single displacement reaction. Enthalpy change of reaction 3 represents the heat evolved as the hydrogen and hydroxide ion form water via a neutralization reaction. 4. Apply Hess's Law using the sum of reaction 1 and reaction 3 to find the experimental value of AH for reactions 2. Show your work below. NaOH(s) → AlaaetOHfe9) NaOH(s) + HCl(aa) → H2Om + NaCl(a) AlaOHag) + HCl(ag) → H200 + NaCl(ag) AH = -1.129 kJ AH = -2.5 k] AH = -1.400 kJ AH = -1.129 kJ + (-1.400 kJ) = -2.5 kJ 5. Calculate the percent error between the value of AH for reaction 2 and the sum of AH for reaction 1 plus AH for reaction 3. (Assume AH for reaction 2 to be the accepted value). Show your work. Account for any similarity or difference.
Transcribed Image Text:2. Write net ionic equations for Reactions 1, 2 and 3. Consider the heat given off in your reactions; include the heat evolved in kJ/mole for each reaction. Reaction1: Heat of NaOH solution (solid NaOH + H2O) NaOH(s) > Na(ag) + OH (aa) Molar mass of NaOH: 39.998 g/mol mass NaOH п (Na0H) 3D M NaOH 1.0 g п (NaOH) = 0.025 mol 39.998 g/mol 1.129 kJ ΔΗ - -= - 45.16 kJ /mol 0.025 mol Reaction 2: Heat of NaOH solution (solid NaOH + HCI solution) NaOH(s) + HCl(ag) → H2Oa) + NaClao) mass NaOH п (NaOH) %3D M NaOH 1.0 g п (Na0H) = 0.025 mol 39.998 g/mol - 2.5 k) ΔΗ 100.0 kJ/mol 25: Reaction 3: Heat of Neutralization (NaOH solution + HCI solution) NaOH(ag) + HCl(ag) → H200 + NaCl(ag) mass NaOH п (NaOH) 3D M NaOH 1.0 g п (Na0H) %3 = 0.025 mol 39.998 g/mol -1.400 kJ ΔΗ- -56 kJ /mol 0.025 mol pg. 7 3. The energy in Reaction 1 represents the energy of solution for one mole of NaOH (s). Look at the net ionic equations for Reactions 2 and 3, and make a similar statement concerning the significance of AH for reactions 2 and 3. Enthalpy change of reaction 2 represents the heat evolved as the hydrogen ion displaces the sodium ion, creating a single displacement reaction. Enthalpy change of reaction 3 represents the heat evolved as the hydrogen and hydroxide ion form water via a neutralization reaction. 4. Apply Hess's Law using the sum of reaction 1 and reaction 3 to find the experimental value of AH for reactions 2. Show your work below. NaOH(s) → AlaaetOHfe9) NaOH(s) + HCl(aa) → H2Om + NaCl(a) AlaOHag) + HCl(ag) → H200 + NaCl(ag) AH = -1.129 kJ AH = -2.5 k] AH = -1.400 kJ AH = -1.129 kJ + (-1.400 kJ) = -2.5 kJ 5. Calculate the percent error between the value of AH for reaction 2 and the sum of AH for reaction 1 plus AH for reaction 3. (Assume AH for reaction 2 to be the accepted value). Show your work. Account for any similarity or difference.
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