5. Calculate the gravitational force between two 150 kg objects located 25 m apart. (150)(150) 25 F = 6.673x10- _N 6. Calculate the change in the gravitational force between the two objects if the distance between the two objects doubles. -" (150)(150) 50 F = 6.673×10 N 7. Use the inverse square law to describe the relationship between the gravitational force and the distance between the two objects. What was the scale factor of the distances? What is the inverse square of the scale factor? Multiply the gravitational force in question 6 by the inverse square of the scale factor. How does this relate to the gravitational force in question 7 when the distance is doubled?

5. Calculate the gravitational force between two 150 kg objects located 25 m apart. (150)(150) 25 F = 6.673x10- _N 6. Calculate the change in the gravitational force between the two objects if the distance between the two objects doubles. -" (150)(150) 50 F = 6.673×10 N 7. Use the inverse square law to describe the relationship between the gravitational force and the distance between the two objects. What was the scale factor of the distances? What is the inverse square of the scale factor? Multiply the gravitational force in question 6 by the inverse square of the scale factor. How does this relate to the gravitational force in question 7 when the distance is doubled?

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Description: Gravitational Forces (A)Gravitational, Electrical, Magnetic, and Nuclear ForcesMath ConnectionsLaw of Universal Gravitation (continued)This law states that any two objects with mass exert a gravitational force on each other. The forcehas the same ma

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Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!

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Gravitational Forces (A)
Gravitational, Electrical, Magnetic, and Nuclear Forces
Math Connections
Law of Universal Gravitation (continued)
This law states that any two objects with mass exert a gravitational force on each other. The force
has the same magnitude on each object. The magnitude is directly proportional to the product of
the objects' masses. It is inversely proportional to the square of the distance between the objects.
Where,
F = gravitational force between two objects
= gravitational constant = 6.673 × 1011 N x m²/kg?
m, and m, = masses of the two objects in kg
d = distance between the two objects in m
m,m,
F, = G(
d
5. Calculate the gravitational force between two 150 kg objects located 25 m apart.
(150)(150)
25?
F = 6.673×10¯"
N
6. Calculate the change in the gravitational force between the two objects if the distance between
the two objects doubles.
F = 6.673x10-" (150)(150)
50?
7. Use the inverse square law to describe the relationship between the gravitational force and the
distance between the two objects.
What was the scale factor of the distances?
What is the inverse square of the scale factor?
Multiply the gravitational force in question 6 by the inverse square of the scale factor.
How does this relate to the gravitational force in question 7 when the distance is doubled?
8. If the gravitational force between two objects is 16 N, and the distance between the objects
doubles, what is the resulting gravitational force? Use the inference you made in question 7 to
calculate the resulting force.
16
N

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