5. Below are listed the atomic weight, density, and atomic radius for three hypothetical elements.For each determine whether its crystal structure is face-centered cubic (FCC), body-centered cubic(BCC) or simple cubic (SC) and then justify your determination.ElementsAtomic Weight (g/mol)Density (g/cm')Atomic Radius (nm)A107.613.420.13377.48.220.12550,95,960,132

Crystal StructuresAcademic Resource CenterCrystallinity: Repeating or periodic array over…

5. Below are listed the atomic weight, density, and atomic radius for three hypothetical eleme For each determine whether its crystal structure is face-centered cubic (FCC), body-centered cu (BCC) or simple cubic (SC) and then justify your determination. Elements Atomic Weight (g/mol) Density (g/cm') Atomic Radius (nm) A 107.6 13.42 0.133 77.4 8.22 0.125 50,9 5,96 0,132

5. Below are listed the atomic weight, density, and atomic radius for three hypothetical eleme For each determine whether its crystal structure is face-centered cubic (FCC), body-centered cu (BCC) or simple cubic (SC) and then justify your determination. Elements Atomic Weight (g/mol) Density (g/cm') Atomic Radius (nm) A 107.6 13.42 0.133 77.4 8.22 0.125 50,9 5,96 0,132

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question 11 of 15 A crystal was analyzed using X-ray diffraction with radiation from a chromium source. The observed angle was 7.99°. Element 1 (pm) CO 179 Determine the distance between layers of the crystal. Cr 229 Cu 154 Fe 194 Мо 71.1 d = pm
Topic: Solidification & Crystal Imperfections QUESTION 1 Calculate the fraction of atom sites that are vacant for lead at its melting temperature of 600 K. Assume energy for vacancy formation of 0.55 eVlatom. QUESTION 2 Calculate the number of vacancies per cubic meter in iron at 850°C. The energy for vacancy formation is 1.08 eVlatom. Furthermore, the density and atomic weight for Fe are 7.65 g/cm' and 55.85 g/mol, respectively. QUESTION 3 Calculate the activation energy for vacancy formation in aluminum, given that the equilibrium number of vacancies at 500°C (773 K) is 7.57 x 10 m°. The atomic weight and density (at 500°C) for aluminum are, respectively, 26.98 g/mol and 2.62 g/cm.
4. Calculate the enthalpy of vaporization of a liquid that has a vapor pressure of 144.589 mmHg at -40.6 °C and 598.444 mmHg at -10.5 °C. Based on that value, calculate the normal boiling point of the substance. 5. An element occupies a face-centered cubic unit cell with an edge length of 380.36 pm. The element has a density of 1.2410x104 kg m-³. What is the name of the element? 6. Calculate the density of niobium if it occupies a body-centered cubic unit cell with an atomic radius of 142.83 pm.
A hypothetical element, Le, has a body centered cubic structure with a density of 7.98 g/cm3. Calculate its atomic radius in pm. Atomic Mass: Le: 57.621 g/mol Round your answer to 2 decimal places.
QUESTION 5 Considering pure metals, which of the following statements is (or are) correct about their cubic unit cells? a) In the FCC (faced center cubic) structure of a pure metal, the edge length of the cubic unit cell (d) and the radius of the metal atom (r) has the following relation: 4 r2 = 2 d2. b) A FCC (face center cubic) unit cell has a greater number of net atoms than a BCC (body center cubic) unit cell has. a) only O b) only Both a) and b) are correct. Neither a) nor b) is correct.
A metal has a radius of 0.153 nm, and a planar density of 7.5516551453132 nm-2 in the (110) plane. What is the crystal structure of the material? a. Something else; atomic radius 0.153 nm b. BCC with atomic radius 0.153 nm c. FCC with atomic radius 0.153 nm d. HCP with atomic radius 0.153 nm
A/ determine the atomic weight of copper which has atomic radius of 0.128 nm and theoretical density of 8.89g/cm3 B/ calculate the equilibrium number of vacancies per cubic for iron at 1000c. the energy for vacancy formation is 1.9 J/atom, the atomic weight and density for iron are 60.5 g/mol and 7.4 g/cm3 .respectively
5. The space-filling representation provided below is an example of a atom(s). unit cell, which contains a. body centered cubic, 2 atom IS b. face centered cubic, 4 atoms c. primitive cubic, 1 atom d. body centered cubic, 4 atom IS e. face centered cubic, 5 atoms
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