5. An object is attached to a spring and completes only one cycle (i.e. goes back and forth and stops). The object reaches its maximum velocity after 0.250 seconds of motion. Calculate the its angular frequency and the spring constant if the object is 0.125 kg.

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**Problem Statement:**

An object is attached to a spring and completes only one cycle (i.e. goes back and forth and stops). The object reaches its maximum velocity after 0.250 seconds of motion. Calculate its angular frequency and the spring constant if the object is 0.125 kg.

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**Explanation:**

This problem involves a spring-mass system in simple harmonic motion (SHM). In SHM, the object oscillates back and forth around an equilibrium point, and several key parameters can define its motion, including angular frequency and spring constant.

**Key Parameters:**

1. **Angular Frequency (ω):** Determines how fast the object oscillates and is measured in radians per second (rad/s).
2. **Spring Constant (k):** A measure of the stiffness of the spring and is measured in Newtons per meter (N/m).
3. **Mass (m):** Given as 0.125 kg, it is the weight of the object attached to the spring.

**Calculation Steps:**

To find the angular frequency and spring constant, we usually apply the equations of simple harmonic motion:

- **Angular Frequency (ω):** Given by the formula \(ω = \frac{2π}{T}\), where T is the period of motion.
- **Spring Constant (k):** Related to the angular frequency and mass by the formula \(k = mω^2\).

In this scenario, additional information such as maximum velocity or displacement might be necessary for complete calculations, which are not provided here but can be inferred from the scenario and additional study on SHM principles.

This is a typical problem encountered in physics to test understanding of oscillations and wave mechanics.
Transcribed Image Text:**Problem Statement:** An object is attached to a spring and completes only one cycle (i.e. goes back and forth and stops). The object reaches its maximum velocity after 0.250 seconds of motion. Calculate its angular frequency and the spring constant if the object is 0.125 kg. --- **Explanation:** This problem involves a spring-mass system in simple harmonic motion (SHM). In SHM, the object oscillates back and forth around an equilibrium point, and several key parameters can define its motion, including angular frequency and spring constant. **Key Parameters:** 1. **Angular Frequency (ω):** Determines how fast the object oscillates and is measured in radians per second (rad/s). 2. **Spring Constant (k):** A measure of the stiffness of the spring and is measured in Newtons per meter (N/m). 3. **Mass (m):** Given as 0.125 kg, it is the weight of the object attached to the spring. **Calculation Steps:** To find the angular frequency and spring constant, we usually apply the equations of simple harmonic motion: - **Angular Frequency (ω):** Given by the formula \(ω = \frac{2π}{T}\), where T is the period of motion. - **Spring Constant (k):** Related to the angular frequency and mass by the formula \(k = mω^2\). In this scenario, additional information such as maximum velocity or displacement might be necessary for complete calculations, which are not provided here but can be inferred from the scenario and additional study on SHM principles. This is a typical problem encountered in physics to test understanding of oscillations and wave mechanics.
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