5. An Lissajous Figure is defined by x = 3 cos(3r) and y = 3 sin(51) on the f-interval [0, 2n]. (a) Find dy dx (b) Find two (x, y) points where the tangent line is horizontal. (c) Find an (x, y) point in Quadrant II where the tangent line is vertical.

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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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5. An Lissajous Figure is defined by x=3 cos(31) and y=3sin(5t) on the t-interval [0, 2].
(a) Find dy
dx
(b) Find two (x, y) points where the tangent line is horizontal.
(c) Find an (x, y) point in Quadrant II where the tangent line is vertical.
(d) Use L=
dx
dt
dy
dt
dt to approximate the arc length of the ellipse.
(e) Recall that acceleration is the second derivative of the position function. Find the
acceleration in the x-direction when t = 3.7, accurate to 4 decimal places.
Transcribed Image Text:5. An Lissajous Figure is defined by x=3 cos(31) and y=3sin(5t) on the t-interval [0, 2]. (a) Find dy dx (b) Find two (x, y) points where the tangent line is horizontal. (c) Find an (x, y) point in Quadrant II where the tangent line is vertical. (d) Use L= dx dt dy dt dt to approximate the arc length of the ellipse. (e) Recall that acceleration is the second derivative of the position function. Find the acceleration in the x-direction when t = 3.7, accurate to 4 decimal places.
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