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#5. An inverting op-amp is shown in Fig. 2. Calculate the closed loop gain Vo/Vi when the switch is in position 2. Use LTspice and/or hand analysis to solve the problem. Vi 5 ΚΩ ww 12 ΚΩ www 80 ΚΩ www 2 ΜΩ www 1 - 2 იო 10 ΚΩ Figure 2: Inverting Op-Amp Solution #5 R 12 (Position 1) G= = -2.4 V₁ R₁ 5 80 (Position 2) -16 Vi 5 2000 (Position 3) = -400 Vi 5 (a) -2.4, (b) -16, (c) -400

#5. An inverting op-amp is shown in Fig. 2. Calculate the closed loop gain Vo/Vi when the switch is in position 2. Use LTspice and/or hand analysis to solve the problem. Vi 5 ΚΩ ww 12 ΚΩ www 80 ΚΩ www 2 ΜΩ www 1 - 2 იო 10 ΚΩ Figure 2: Inverting Op-Amp Solution #5 R 12 (Position 1) G= = -2.4 V₁ R₁ 5 80 (Position 2) -16 Vi 5 2000 (Position 3) = -400 Vi 5 (a) -2.4, (b) -16, (c) -400

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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#5. An inverting op-amp is shown in Fig. 2. Calculate the closed loop gain Vo/Vi when the switch is in position 2. Use LTspice and/or hand analysis to solve the problem. Vi 5 ΚΩ ww 12 ΚΩ www 80 ΚΩ www 2 ΜΩ www 1 - 2 იო 10 ΚΩ Figure 2: Inverting Op-Amp
Transcribed Image Text:#5. An inverting op-amp is shown in Fig. 2. Calculate the closed loop gain Vo/Vi when the switch is in position 2. Use LTspice and/or hand analysis to solve the problem. Vi 5 ΚΩ ww 12 ΚΩ www 80 ΚΩ www 2 ΜΩ www 1 - 2 იო 10 ΚΩ Figure 2: Inverting Op-Amp
Solution #5 R 12 (Position 1) G= = -2.4 V₁ R₁ 5 80 (Position 2) -16 Vi 5 2000 (Position 3) = -400 Vi 5 (a) -2.4, (b) -16, (c) -400
Transcribed Image Text:Solution #5 R 12 (Position 1) G= = -2.4 V₁ R₁ 5 80 (Position 2) -16 Vi 5 2000 (Position 3) = -400 Vi 5 (a) -2.4, (b) -16, (c) -400
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