5. A vice president in charge of sales for a large corporation claims that salespeople are averaging no more than 15 sales contacts per week. (He would like to increase this figure.) As a check on his claim, n = 36 salespeople are selected at random, and the number of contacts made by each is recorded for a single randomly selected week. The mean and variance of the 36 measurements were 17 and 9, respectively. Does the evidence contradict the vice president's claim? Use a test with level a = .05.
5. A vice president in charge of sales for a large corporation claims that salespeople are averaging no more than 15 sales contacts per week. (He would like to increase this figure.) As a check on his claim, n = 36 salespeople are selected at random, and the number of contacts made by each is recorded for a single randomly selected week. The mean and variance of the 36 measurements were 17 and 9, respectively. Does the evidence contradict the vice president's claim? Use a test with level a = .05.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Hello please answer 5 & 6

Transcribed Image Text:No: um 13,20
Ha: 13,20
Part 2. Mean
4. The hourly wages in a particular industry are normally distributed with mean $13.20 and standard
deviation $2.50. A company in this industry employs 40 workers, paying them an average of $12.20
per hour. Can this company be accused of paying substandard wages? Use an a = .01 level test.
Popl. mean hourly wages in particular industry (u) = $13.20
Popl, std, deviation of hourly wages in a particular industry (0) = $2.50
Randomly selected no. of workers (n) = 40
Test stat:
2 = x-µ/0//
= 12.20-13,20/2,50/ 40
= -2.62982
Sample mean hourly wages (x) = $12.20
Level of signif. (a) = 0,01
p value:
Since alt, hypo, has < sign, so it is left tailed test
value = P(Z < Zstat)
P
0.005705
= P(Z < -2.52982)
Using excel command, NORMSDIST (z score )
=NORMSDIST-2.52982)
So,
p value = 0,005706
Decision rule:
If p value < level of signif. (a) then reject Ho otherwise fail to reject Ho
Here, p value < a
Hence, reject Ho
1078
Conclusion
There is suffi. evid, to support that the company can be accused of paying
substd, wages
5. A vice president in charge of sales for a large corporation claims that salespeople are averaging no
more than 15 sales contacts per week. (He would like to increase this figure.) As a check on his claim,
n = 36 salespeople are selected at random, and the number of contacts made by each is recorded for
a single randomly selected week. The mean and variance of the 36 measurements were 17 and 9,
respectively. Does the evidence contradict the vice president's claim? Use a test with level a = .05.
1070
There is suffi. evid, to support that the company can be
accused of paying substd, wages
6. Listed below are brain volumes (in centimeters cubed) of unrelated subjects used in a study. Use a
0.05 significance level to test the claim that the population of brain volumes has a mean equal to
1100.8 centimeters cubed.
963
1027
1271
1174
1066
1348
1099
1204
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