(5). A satellite is in a circular orbit around the Earth at an altitude of h = 1, 250 km above the Earth's surface. The radius of the Earth is equal to Rr =6.37x0°m, the mass is =5.98x1024 kg G= 6.67 x10-11 MẸ Nm²/kg? (a) Find the speed of the satellite, (b) Find the period, which is the time it takes to make one complete revolution. (c) Find the centripetal acceleration. Consider a horizontal circle

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Chapter1: Units, Trigonometry. And Vectors
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(5). A satellite is in a circular orbit
around the Earth
at an altitude of h = 1, 250 km
above the Earth's
surface. The radius of the
Earth is equal to
R: =6.37x10°m, the mass is
Mp
=5.98x1024 kg
G- 6.67 х10-11
Nm²/kg?
(a) Find the speed of the satellite,
(b) Find the period, which is the time
it takes to make one complete
revolution.
(c) Find the centripetal
acceleration. Consider a
horizontal circle.
R = RE + h
Transcribed Image Text:(5). A satellite is in a circular orbit around the Earth at an altitude of h = 1, 250 km above the Earth's surface. The radius of the Earth is equal to R: =6.37x10°m, the mass is Mp =5.98x1024 kg G- 6.67 х10-11 Nm²/kg? (a) Find the speed of the satellite, (b) Find the period, which is the time it takes to make one complete revolution. (c) Find the centripetal acceleration. Consider a horizontal circle. R = RE + h
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