5. A pilot column breakthrough test has been performed with a wastewater that has a trichloroethylene (TCE) concentration of 400 mg/L as TOC (total organic carbon). Pertinent design data are ID = 0.095 m, length = 1.04 m, mass of carbon = 2.98 kg, liquid flow rate = 17.42 L/hr, unit liquid flow rate = 0.679 L/s-m², and packed carbon density = 401 g/L. The breakthrough data are given in Table 1. Determine: a. The liquid flow rate in bed volumes per hour and the volume of liquid treated per unit mass of carbon using an allowable breakthrough concentration of 35 mg/L of TOC. in kg/kg. b. The kinetic constants ki in L/s-kg and qo Table 1. Throughput Volume Effluent TOC (mg/L) (L) 15 69 159 273 379 681 965 1105 1215 1287 1408 1548 12 16 24 16 16 20 28 32 103 211 350 400

5. A pilot column breakthrough test has been performed with a wastewater that has a trichloroethylene (TCE) concentration of 400 mg/L as TOC (total organic carbon). Pertinent design data are ID = 0.095 m, length = 1.04 m, mass of carbon = 2.98 kg, liquid flow rate = 17.42 L/hr, unit liquid flow rate = 0.679 L/s-m², and packed carbon density = 401 g/L. The breakthrough data are given in Table 1. Determine: a. The liquid flow rate in bed volumes per hour and the volume of liquid treated per unit mass of carbon using an allowable breakthrough concentration of 35 mg/L of TOC. in kg/kg. b. The kinetic constants ki in L/s-kg and qo Table 1. Throughput Volume Effluent TOC (mg/L) (L) 15 69 159 273 379 681 965 1105 1215 1287 1408 1548 12 16 24 16 16 20 28 32 103 211 350 400

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: = 5% Volatile solids = 80%. Note: 1 ft = 7.5 gallons No matches found. Select one: a. 4.2 lb…

Q: te is 2500 m3/day with a soluble BOD5 of 250 mg/L. The average wastewater temperature is 16 oC.…

A: Bio - Towers : bio towers are only vertical streaming channels having more noteworthy channel media…

Q: 6. In a wastewater treatment plant, a coarse screen is used. The approach velocity of the wastewater…

A: Given, Approach velocity=0.5 m/sVelocity through clean bar = 0.75 m/s Head loss coefficient for…

Q: There is a sedimentation tank that is used to remove suspended solid particles (diameter of 100 um…

A: Given Data : ρp=2650 kg/m3 ρf=999.7 kg/m3 Dp=100×10-6 m μ=1.307×10-3 Ns/m2

Q: 1. Determine the 5-day 20°C BOD of a wastewater if the 3-day 10°C BOD is 100 mg/L. Assume a…

Q: Compute the required volume of the aeration tank. If the SWD is to be 15 ft and the tank length to…

Q: A untreated waste water enters a stream as shown in figure. The concentration of sodium in the…

A: Given data, The concentration of sodium =15 mg/l flow rate=20 m3 /sec The concentration of sodium in…

Q: Calculate theoretical oxygen requirement (kg/day) of a complete - mix activated sludge process…

A: To calculate the theoretical oxygen requirement, we need to consider the oxygen demand for carbon…

Q: Question: A wastewater with a BOD5 of 326 mg/L and a Total Suspended Solids (TSS) of 392 mg/ is sent…

Q: sludge to meet their NPDES permit of 15 mg/L BOD5. The mixed liquor concentration is 1,000 mg/L…

Q: Q3/ If the discharge of the river is 110 ft /sec and the boron concentrations for the river and the…

A: Discharge of river QR=110 ft3/sectotal discharge after mixing waste water QT =185 ft3/swaste water…

Q: The BOD just downstream from a wastewater pipe is 12.9 mg/L and the DO (dissolved oxygen) is 8.6…

A: Given, BOD just downstream from wastewater pipe, L = 12.9mg/l DO at just downstream from wastewater…

Q: An activated sludge system operates at a flow rate (Q) of 400 m³/day (and an HRT. 0.129 day) with an…

A: Given:- Q=400 m3/day HRT=0.129day BOD=300mg/L Ks=200 mg/L To find:- mxed liqour concentration…

Q: A storm sewer is mixed into a small streams. the stream before the mixing point has a NaCl…

Q: Analysis of a wastewater sample provided: TS: 250 mg/L; TDS: 35 mg/L; FSS: 35 mg/L. a) What is TSS…

A: Given TS=250mg/l TDS=35mg/l TSS=35mg/l To find TSS and VSS

Q: wastewater plant produces 1200 kg of dry solids per day at a moisture content of 92% .the solids are…

A: GIVEN DATA:-⇒Dry solids per day @ 92% moisture content = 1200 kg⇒Volatile solids= 75%⇒Volatile…

Q: Find the time and distance downstream at whoch the oxyfen deficit is a macimum b. Find the minimum…

Q: ed sludge system treats wastewater from an industry with a flow rate of 10 y. The BOD of the raw…

Q: A wastewater sample was diluted 10% with tap water for conducting BOD Test. The DO content in…

Q: A 3 mL industrial wastewater sample is added to a BOD bottle (300mL). The initial D.O.…

Q: 4. Wastewater sample was prepared and incubated at 20°C for 5 days for BOD analysis. Sample volume…

Q: The chloride concentration in a brine waste flow of 6.3 L/s is 15000 mg/L. The river flow upstream…

A: step 1-

Q: Wastewater from a primary treatment tank is to undergo secondary treatment in an activated sludge…

A: Given data-Hydraulic retention time (t) is 6hMean cell residence time is 7 daysBOD content at inlet…

Q: what aerobic reactor volume and operating SRT are required to treat a 20 MGD domestic wastewater…

A: Activated sludge process Assumptions All the reaction occurred in the aeration tank only The…

Q: After primary treatment, a municipal wastewater contains 150 mg/L BOD5. The wastewater flow of 0.44…

A: BOD5=150 mg/LQ=0.44 m3/s (10 MGD)SRT = 12dHRT=6h To determine- Limiting value of SRT

Q: 6. A tertiary treatment plant treats a municipal secondary effluent and is to employ fixed-bed…

A: Reference : Environmental Engineering, Waste water treatment plant. Given : Flow, COD, Contact time…

Q: Determine the diameter of a trickling filter for a wastewater flowing at the rate of (13500/100)…

A: Wastewater flowing at the rate of (Q = 13500/100) gallons per minute. Concentration for the…

Q: Using the data presented below, compute the total amount of sludge produced daily in the primary…

A: please find attached solution below.

Q: A lagoon with a volume of 1500 m3 reieves an industrial wastewater flow of 100 m3/day containing a…

A: Volume = 1500 m3 Waste water flow = 100m3/day Concentation = mg/l

Q: (a) (b) Sludge thickening can be implemented using several methods. Describe TWO (2) differences…

A: Sludge can be defined as the residue that is left after the treatment of sewage. Sludge can be…

Q: Use Thomas' method to determine the BODs, k10 rate and BODultimate for a wastewater which gives…

A: A wastewater sample is given. BOD at various time intervals is given in table. Using Thomas' method,…

Q: 2. The average wastewater flow from a community of 20,000 is 125 gpcd. The 5 day, 20 deg C BOD is…

Q: 10. A 15,000 ft" conventional activated sludge system has a recycle ratio of 0.38, an influent flow…

Q: Then, you were asked to find out the biodegradability of this wastewater by conducting a 5-day…

Q: Determine the Aeration Basin Dimensions for a town of 200,000 population. Mixed Liquor Suspended…

A: Following is the given information: Population = 200,000. Mixed Liquor Suspended Solids = 3500…

Q: The 550-bed Atlanta Hospital has a small, activated sludge plant to treat wastewater from the…

A: Given, BOD5 after primary settling, So = 450 mg/L MLVSS = 2,600 mg/L To find : F/M ratio

Q: sand bed filter is 50 ft in diameter and filled to a depth of 20 ft with sand. The sand particle…

Concept explainers

Storm Sewers and Detention

The storm drains system transports rainwater or stormwater and other runoff from roads, parking lots, and roof downpipes directly to nearby creeks, rivers, or the sea without any treatment.

Question

5. A pilot column breakthrough test has been performed with a wastewater that has a trichloroethylene
(TCE) concentration of 400 mg/L as TOC (total organic carbon). Pertinent design data are ID =
0.095 m, length = 1.04 m, mass of carbon = 2.98 kg, liquid flow rate = 17.42 L/hr, unit liquid flow
rate = 0.679 L/s-m², and packed carbon density = 401 g/L. The breakthrough data are given in Table
1. Determine:
a. The liquid flow rate in bed volumes per hour and the volume of liquid treated per unit mass of
carbon using an allowable breakthrough concentration of 35 mg/L of TOC.
b. The kinetic constants ki in L/s-kg and qo in kg/kg.
Table 1.
Throughput Volume
(L)
15
69
159
273
379
681
965
1105
1215
1287
1408
1548
Effluent TOC
(mg/L)
12
16
24
16
16
20
28
32
103
211
350
400

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Data

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Trending now

This is a popular solution!

Step by step

Solved in 7 steps with 14 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A CMAS treatment system must be designed for a municipal wastewater and the following operating conditions: • Effluent flow of 0.39 m³/s leaving the primary clarifier Effluent soluble BOD; of 310 mg/L leaving the primary clarifier 20 mg/L of soluble BOD5 allowed in the effluent from the secondary clarifier Negligible suspended solids in the effluent from the secondary clarifier • Volatile suspended solids concentration of 4300 mg/L in the aeration tank • In the laboratory under log-growth conditions, the microorganisms used in the aeration tank can convert 100 g soluble BODS into 55 g VSS • Microorganisms in the CMAS system have a death rate constant of 0.05 d'. Sludge age in the CMAS treatment system will be 4 days (a) Determine the % treatment efficiency for soluble BOD; required in the CMAS system. (b) Determine the required volume of the aeration tank (in m²) and HRT (in h). (c) Determine the food-to-microorganism ratio (in d') and the specific substrate utilization ratio (in d').…
A continuous stirred tank reactor (CSTR) Activated Sludge Process is used to treat municipal wastewater after primary sedimentation. The following data is available: Primary Effluent Flow Rate (Q) Primary Effluent BOD Concentration (So) Secondary Effluent Biomass Concentration (Xe) Mixed Liquor Biomass Concentration (X) Solids Retention Time (SRT) Waste Sludge Flow Rate (Qw) Value 450 200 O 0 3,000 5 8 Biomass Concentration in RAS (XR) 8,000 O 250 million gallons, 0.28 gBOD/gVSS.d, 13.3 hours 107 million gallons, 0.28 gBOD/gVSS.d, 5.7 hours O 107 million gallons, 0.42 gBOD/gVSS.d, 5.7 hours 107 million gallons, 0.28 gBOD/gVSS.d, 12.2 hour Unit mgd mg/l mg/1 mg/l days mgd The bioreactor volume (V), F/M ratio, and HRT are respectively: mg/l
What aerobic reactor volume and operating SRT (8) are required to treat a 20 MGD domestic wastewater flow from an initial ultimate BOD - 300 mg/L to an effluent BODu 5 mg/L assuming a complete mix activated sludge system? Use the design information below assuming 1st order kinetics. MLVSS = 3,000 mg/L - X Y-05 K=0.1 L/mg'day (1st order degradation rate constant) K₂ -0.1 day 1 Answers are given as Aeration Tank Volume, Operational O 0.1 MG, 2.5 days O 19.65 MG, 20 days O 3.93 MG, 6.7 days 5.2 MG, 5.1 days
A storm sewer is mixed into a small stream. The stream before the mixing point has a NaCi concentration of 25 mg/L. If the storm sewer has a Nacl concentration of 1.8 g/L and the storm sewer flowrate is 2.5 L/min, calculate for the concentration of the salt in the stream after the discharge point (mixing point). The stream has a flowrate of 2.6 cu.m/s. Assume a complete mixing of the storm sewer flow and the stream flow. Assume also that the salt is nonreactive and that the system is at steady state.
6. After your flash mix the water was sent to a clarification basin that was 24 feet in diameter and 20 feet tall. What was the detention time in hours of 0.43 MGD? 5.4 hours 4.3 hours 3.8 hours 2.3 hours After the water leaves your sedimentation basin, it is ready for filtration. Your two filters measure 10 feet in diameter. What is the filtration rate is gpm for your flow of 0.43 MGD? 19 gpm/sq/ft 29 gpm/sq/ft 39 gpm/sq/ft 49 gpm/sq/ft You have had a filtration breakthrough (failure) and have brought your old roughing filtration system on line. The old filter is 8 feet square and 4 feet deep. What is the filtration rate in gpm/sq/ft for your flow of 0.43 MGD? 10.33 gpm/sq/ft 8.55 gpm/sq/ft 5.99 gpm/sq/ft 4.66 gpm/sq/ft
An activated sludge wastewater treatment system was designed and operated in a steadystate under the following conditions:• Reactor volume of 10,000 m3in total;• Sludge concentration (MLSS) of 3200 mg/L in the reactor;• Return sludge concentration at 8000 mg/L (the underflow of the secondary clarifier)• Each day, 400 m3 of underflow sludge (return sludge) was wasted as excesssludge;What is the average Sludge Residence Time (SRT)?
Q-The MLSS concentration in an aeration tank is 2000 mg/l and the sludge volume after 30 minutes of setting in a 1000 ml graduated cylinder is 175 ml. Find the value of sludge density index (SDI).
In a BOD test, 5 ml of wastewater (with no dissolved oxygen) is diluted with 295 ml of water containing 8.5 mg/1 of dissolved oxygen. After 5 days incubation at 25°C, the dissolved oxygen content of the mixture is 5 mg/1. Temperature coefficient can be taken as 1.047 and BOD rate constant is 0.23 per day (base e) at 20°C. The ultimate biochemical oxygen demand of the wastewater is
3. A 100 mL of wastewater sample was drying on a 0.5 g empty dish weight at 104 °C to weight 0.5625 g. Another 100 mL of the same wastewater was first filtered and the filtrate was dried on a 0.5 g dish at 104 °C to weight 0.5325 g. Determine in mg/L the:a) TSb) TSSc) TDSd) VSS assuming it represents 70% of TSS
COURSE: ENV 2
Please Solve this question.
Q- If the BOD3 of a wastewater sample is 75 mg/L and reaction rate constant k (base e) is 0.345 per day, find the amount of BOD remaining in the given sample after 10 days.