5. A non uniform rod with mass m=2 kg and length L= 1 m is pivoted at 0.75 m from the left end as in the fig below. A mass=0.5 kg hanged 0.95 m from the left end. The rod is in equilibrium. Find the x position of the center of mass of the rod from the left end? Хсм. = опш X=0 L 0.75 0.95
5. A non uniform rod with mass m=2 kg and length L= 1 m is pivoted at 0.75 m from the left end as in the fig below. A mass=0.5 kg hanged 0.95 m from the left end. The rod is in equilibrium. Find the x position of the center of mass of the rod from the left end? Хсм. = опш X=0 L 0.75 0.95
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Transcribed Image Text:5. A non uniform rod with mass m = 2 kg and length L=1 m is pivoted at 0.75 m from the left end as in the
fig below. A mass=0.5 kg hanged 0.95 m from the left end. The rod is in equilibrium. Find the x position of
the center of mass of the rod from the left end?
Хсм = опш
X=0
L
0.75
0.95
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