5. A lens whose focal length is 40cm forms a Fraunhofer diffraction pattern due to a slit 0.3mm side. Find the distance of the first secondary maximum form the axis. Wavelength used is 589.3nm.
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- Needs Complete typed solution with 100 % accuracy.13. The Hubble space telescope has diffraction-limited optics determined by the aperture (mirror size) of 2.40 m diameter. It detects light emitted from two stars having a wavelength of 656 nm. The two stars are very close to each other and are at a distance of 7.57 x 10¹7 m from Earth. If the telescope is just able to resolve the stars as separate images, find the approximate distance separating them in meters.While flying at an altitude of 9.50 km, you look out the window at various objects on the ground. If your ability to distinguish two objects is limited only by diffraction, find the smallest separation between two objects on the ground that are distin- guishable. Assume your pupil has a diameter of 4.0 mm and take A = 575 nm.
- 1- If we have an etalon (a glass blade) with a thickness of 1 cm and a refractive index of 2, what will be the maximum and minimum total reflection? What is its total reflection coefficient for a wavelength of 500 nm?A diffraction grating with n = 3.5E-05 lines/nm is used to separate two colors of light. The angle between their first maxima is Δθ ≡ θ1 - θ2 = 0.38 degrees, and the first light has wavelength λ1 = 629 nm. a) Find θ1 using n and λ1 in radians. b) Find θ2 in radians.4. Light of wavelength 589 nm is used to view an object under a microscope. If the aperture of the objective has a diameter of 0.9 cm, what is the limiting angle of resolution? If the light is in the visible range, what would be the maximum limit of resolution for this microscope?
- Optics:Magnesium vapor green light (518.36 nm) impinge on a very long and narrow slit (0.25 mm) in a opaque screen. A large lens with a focal length of 65 cm is located very close to the gap. Determine width of Central maximum created by the lens on the viewing screen in meters.What's the longest wavelength of light you could use to resolve a structure with angular diameter 0.44 mrad, using a microscope with a 1.2-mm-diameter objective lens?12. What is the resolving power of a microscope with a 6.00-mm diameter objective which has f =12.0 mm? (Take the average wavelength of visible light to be about 550 nm) a. 550 nm b. 870 nm c. 1145 nm d. 1342 nm
- 1. The limit to the eye's acuity is actually related to diffraction by the pupil. (a) What is the angle between two just-resolvable points of light for a 3.1 mm-diameter pupil, assuming an average wavelength of 570 nm? rads (b) Take your result to be the practical limit for the eye. What is the greatest possible distance a car can be from you if you can resolve its two headlights, given they are 0.8 m apart? r= km (c) What is the distance between two just-resolvable points held at an arm's length (1 m) from your eye? mm S=In an oil immersed objective microscope, oil of R.I. = 1.4 is used. The O wavelength of illuminating light is 4200 A and the semivertical angle is 45°. The resolving power of microscope is,You've got binoculars with 28-mm-diameter lenses. You're observing two bees on a flower 840 m distant. What's the minimum separation between the bees for you to be able to resolve them as two distinct insects? Assume visible light with 590-nm wavelength.