5. A lens whose focal length is 40cm forms a Fraunhofer diffraction pattern due to a slit 0.3mm side. Find the distance of the first secondary maximum form the axis. Wavelength used is 589.3nm.

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5. A lens whose focal length is 40cm forms a Fraunhofer diffraction pattern due to a slit
0.3mm side. Find the distance of the first secondary maximum form the axis.
Wavelength used is 589.3nm.
Transcribed Image Text:5. A lens whose focal length is 40cm forms a Fraunhofer diffraction pattern due to a slit 0.3mm side. Find the distance of the first secondary maximum form the axis. Wavelength used is 589.3nm.
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