5. A bullet of mass m = 0.02kg exits a gun at a velocity vo= 500 m/s and collides with a stationary block of mass M = 2kg. The bullet passes through the block and emerges with a speed v = 100 m/s. After the collision, the block moves on a frictionless surface a distance d = 1m until it comes D k F= Fe a. Find the velocity of the block after the collision. b. Find the energy that was lost in the collision.

icon
Related questions
Question

A AND B

.A bullet of mass m = 0.02kg exits a gun at a velocity vo= 500 m/s and collides with a stationary
block of mass M = 2kg. The bullet passes through the block and emerges with a speed v = 100
m/s. After the collision, the block moves on a frictionless surface a distance d = 1m until it comes
m o
k
F=FeD
M
a.
Find the velocity of the block after the collision.
b.
Find the energy that was lost in the collision.
If the Force on the bullet inside the gun is described by the function
F = Fo e-x/D
FOD
c. Show that the Work done on the bullet is W =
e
d. If d=0.1m find the initial force Fo on the bullet in the gun
Transcribed Image Text:.A bullet of mass m = 0.02kg exits a gun at a velocity vo= 500 m/s and collides with a stationary block of mass M = 2kg. The bullet passes through the block and emerges with a speed v = 100 m/s. After the collision, the block moves on a frictionless surface a distance d = 1m until it comes m o k F=FeD M a. Find the velocity of the block after the collision. b. Find the energy that was lost in the collision. If the Force on the bullet inside the gun is described by the function F = Fo e-x/D FOD c. Show that the Work done on the bullet is W = e d. If d=0.1m find the initial force Fo on the bullet in the gun
Expert Solution
steps

Step by step

Solved in 2 steps with 5 images

Blurred answer