5. A 0.400 kg mass is attached to the end of a string and is to rotate about the other end, 0.700 m away. The mass begins at rest and undergoes an angular acceleration of 15.0 rad/s. Ignore any gravitational considerations regarding the system.

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Chapter1: Units, Trigonometry. And Vectors
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If the string can withdraw a force of tension that is two times that of what exerts on the mass at t = .500 s , at what time will the string break ? 

Answer = .716 s

3. A 0.400 kg mass is attached to the end of a string and is to rotate about the other end, 0.700 m
away. The niass begins at rest and undergoes an angular acceleration of 15.0 rad/s. Ignore any
gravitational considerations regarding the system.
a) What is the tangential speed of the mass after 2 full revolutions?
V, =rW = 13.591/5
b) What is the centripetal acceleration of the mass after 0.500 s?
7.5rad/s
W:
39.375m/5²
Transcribed Image Text:3. A 0.400 kg mass is attached to the end of a string and is to rotate about the other end, 0.700 m away. The niass begins at rest and undergoes an angular acceleration of 15.0 rad/s. Ignore any gravitational considerations regarding the system. a) What is the tangential speed of the mass after 2 full revolutions? V, =rW = 13.591/5 b) What is the centripetal acceleration of the mass after 0.500 s? 7.5rad/s W: 39.375m/5²
a. 39.37SMs?
c) What is the total acceleration as a magnitude and direction after 0.500 s? Note the direction of
this acceleration as an angle measured relative to the radially inward direction.
ae:39.375m
40.75m/s
Tolel
=14.93°
Transcribed Image Text:a. 39.37SMs? c) What is the total acceleration as a magnitude and direction after 0.500 s? Note the direction of this acceleration as an angle measured relative to the radially inward direction. ae:39.375m 40.75m/s Tolel =14.93°
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