5. 7. d²y dt2 + dy dt d²y dy dt2 dt +4 + 8y = cost + 13y = 3 cos 2t d²y dy 9. +4 +20y=-3 sin 2t dt² dt 6. dt2 d²y dy +4 + 20y = -cos 5t dt² dt d²y dy +2 + y = cos 3t d1² dt 8. dy +6 +8y=-4 cos 3t dt 10.
5. 7. d²y dt2 + dy dt d²y dy dt2 dt +4 + 8y = cost + 13y = 3 cos 2t d²y dy 9. +4 +20y=-3 sin 2t dt² dt 6. dt2 d²y dy +4 + 20y = -cos 5t dt² dt d²y dy +2 + y = cos 3t d1² dt 8. dy +6 +8y=-4 cos 3t dt 10.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Help asap! Help with #5,#8,#9 please !
![In Exercises 1-10, find the general solution of the given equation.
d²y dy
+3
d²y dy
dt²
dt
+3 + 2y = 5 cost
dt² dt
d²y
dy
+3
d12 dt
1.
3.
5.
7.
d²y
dt2
dy
dt
d²y
dt2
+3
d²y
dy
+6
dt2 dt
+4
dt
+ 2y = cost
+ 2y = sint
+ 8y = cost
+ 13y = 3 cos 2t
dy
9.
d²y
+4 + 20y = -3 sin 2t
d12 dt
2.
4.
6.
8.
10.
dy
+6
dt² dt
dt2
+ 2y = 2 sint
+8y=-4 cos 3t
dy
+4 + 20y = -cos 5t
dt
dy
+2 + y = cos 3t
dt² dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F464fe16a-00d5-4182-8379-61bd4b8bbe02%2F15129ada-f842-4ecd-9c67-94f820af552a%2F2o4tllq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In Exercises 1-10, find the general solution of the given equation.
d²y dy
+3
d²y dy
dt²
dt
+3 + 2y = 5 cost
dt² dt
d²y
dy
+3
d12 dt
1.
3.
5.
7.
d²y
dt2
dy
dt
d²y
dt2
+3
d²y
dy
+6
dt2 dt
+4
dt
+ 2y = cost
+ 2y = sint
+ 8y = cost
+ 13y = 3 cos 2t
dy
9.
d²y
+4 + 20y = -3 sin 2t
d12 dt
2.
4.
6.
8.
10.
dy
+6
dt² dt
dt2
+ 2y = 2 sint
+8y=-4 cos 3t
dy
+4 + 20y = -cos 5t
dt
dy
+2 + y = cos 3t
dt² dt
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