5. (1) (ii) Ibuprofen (206.3 g/mol) absorbs at 255 nm and shows a molar absorptivity of 3010 L/mol.cm. A tablet of ibuprofen, 0.6654 g, was ground and 0.2203 g powder was dissolved in 20% methanol in a 100 mL volumetric flask (Solution A). Exactly 5.0 mL of Solution A was diluted in a 50.0 mL flask and the resulting solution showed an absorbance of 0.1228 AU in a 1.00 cm cell. (i) What is the concentration (mol/L) of ibuprofen in the 100 mL stock solution? (ii) Report the amount of ibuprofen in mg/Tablet. Ibuprofen H₂C HCCH; H₂C CH3 -CH-COOH

5. (1) (ii) Ibuprofen (206.3 g/mol) absorbs at 255 nm and shows a molar absorptivity of 3010 L/mol.cm. A tablet of ibuprofen, 0.6654 g, was ground and 0.2203 g powder was dissolved in 20% methanol in a 100 mL volumetric flask (Solution A). Exactly 5.0 mL of Solution A was diluted in a 50.0 mL flask and the resulting solution showed an absorbance of 0.1228 AU in a 1.00 cm cell. (i) What is the concentration (mol/L) of ibuprofen in the 100 mL stock solution? (ii) Report the amount of ibuprofen in mg/Tablet. Ibuprofen H₂C HCCH; H₂C CH3 -CH-COOH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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g 2.png Average absorbance, .129 +0.128 +0.127)/3 = 0.128 Chrome Concentration of Females of Fe volume Q Molarity of Fe(NO₂)) = 0.2M Volume of Fe(NO₂)); = 5.00mL Moles of Fe³+= Molarity x Molarity x volume(L) Moles of Fe³* = 0.2M x 0.0054 = 10³mole 10-mole 500 x 10-3=0.002M [Fe³+] = [SCN¯] = X = ✪ [Fe³] = 0.002mol/L nknown concentrations to determine [FeSCN]at equilibrium in solution 8: Y = 4290X - 0.068 72% (0.127 + 0.068) 4290 0.127=4290X - 0.068 25ml Fe³+ x 0.002 mol/L-¹ 100mL 100% = 4.5 x 10-5mol/L 20ml SCN X 0.002 mol/L-¹ 100mL = 5.00 x 10^4 mol/L^-1 = 4.00 x 10 mol/L-1 W Flask 8 Flask 9 Flask 10 Flask 11 3.png 4.png Part 3: Q8 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: 09 Flask 8 Flask 9 Flask 10 Flask 11 [Fe³+ (mol/L) 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 Average absorbance 0.127 0.166 0.222 69% 0.308 100% [FESCN¹ (mol/L) 4.5 x 10- 5.4 x 10 6.76 x 10-5 8.76 x 10- [SCN (mol/L) 4.00 x 10-4 4 x 10-4 7 x 10-4 1x 10-³ 3 7.png Place the results from calculations 9 and 10 into…
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Substance P has an extinction coefficient of 72.22 mM-1cm-1 at 420nm. 2 μl of Substance P was added to 998 μl water and the Absorbance at 420nm was 0.820. Calculate the mM concentration of the original Substance P solution
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Provide the products, intermediates, and/or reagents for the following reactions:
0.1040 g of a solid sample containing copper was dissolved by acid and transferred to a 250.00 mL volumetric flask and volume was made up with distilled water. The solution was then diluted by a factor of 20. The final solution was analyzed by atomic absorption spectrophotometry and the concentration was found be 3.109 ppm, What is the weight percentage of copper in the original solid sample? Keep four significant figures in your final answer. Do not try to include the "%" in your answer. e.g. if your final answer is 10.01%, only write 10.01 in the box.
Please don't provide handwriting solution
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