5) y=x² +2x + 2 6) y=x² +2x +4 5.5 4.5 3.5 2.5 0.5 Find EXACT VAlUes Of x-intercepts For EACH F UA ction graphed Beiow!

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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## Graph Analysis and X-Intercept Calculation

### Function Graphs and Instructions

**Function 5:**
\[ y = x^2 + 2x + 2 \]

**Function 6:**
\[ y = x^2 + 2x + 4 \]

### Graph Descriptions:

#### Graph for Function 5:
- Title: \( y = x^2 + 2x + 2 \)
- This is a parabolic curve opening upwards.
- The vertex of the parabola is the minimum point on the graph.
- The graph intersects the y-axis at \( y = 2 \).
- Identifying x-intercepts (where the curve crosses the x-axis) is requested.

#### Graph for Function 6:
- Title: \( y = x^2 + 2x + 4 \)
- This is also a parabolic curve opening upwards.
- Similarly, it has its vertex at the minimum point.
- The graph intersects the y-axis at \( y = 4 \).
- Identifying x-intercepts is requested for this function as well.

### Instruction Text:
**Find EXACT VALUES of x-intercepts for EACH function graphed below!**

### Steps to Find the X-Intercepts:

1. **For Function 5:**
   - Set \( y = 0 \) in the equation \( y = x^2 + 2x + 2 \).
   - Solve the quadratic equation \( x^2 + 2x + 2 = 0 \).

2. **For Function 6:**
   - Set \( y = 0 \) in the equation \( y = x^2 + 2x + 4 \).
   - Solve the quadratic equation \( x^2 + 2x + 4 = 0 \).

### Solving Quadratic Equations:
Use the quadratic formula to find the x-intercepts:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Where \( a = 1, b = 2, \) and \( c = 2 \) for Function 5 and \( c = 4 \) for Function 6.

#### Example Calculation for Function 5:
\[ x = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 1 \cdot 2}}{2 \cdot 1}
Transcribed Image Text:## Graph Analysis and X-Intercept Calculation ### Function Graphs and Instructions **Function 5:** \[ y = x^2 + 2x + 2 \] **Function 6:** \[ y = x^2 + 2x + 4 \] ### Graph Descriptions: #### Graph for Function 5: - Title: \( y = x^2 + 2x + 2 \) - This is a parabolic curve opening upwards. - The vertex of the parabola is the minimum point on the graph. - The graph intersects the y-axis at \( y = 2 \). - Identifying x-intercepts (where the curve crosses the x-axis) is requested. #### Graph for Function 6: - Title: \( y = x^2 + 2x + 4 \) - This is also a parabolic curve opening upwards. - Similarly, it has its vertex at the minimum point. - The graph intersects the y-axis at \( y = 4 \). - Identifying x-intercepts is requested for this function as well. ### Instruction Text: **Find EXACT VALUES of x-intercepts for EACH function graphed below!** ### Steps to Find the X-Intercepts: 1. **For Function 5:** - Set \( y = 0 \) in the equation \( y = x^2 + 2x + 2 \). - Solve the quadratic equation \( x^2 + 2x + 2 = 0 \). 2. **For Function 6:** - Set \( y = 0 \) in the equation \( y = x^2 + 2x + 4 \). - Solve the quadratic equation \( x^2 + 2x + 4 = 0 \). ### Solving Quadratic Equations: Use the quadratic formula to find the x-intercepts: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Where \( a = 1, b = 2, \) and \( c = 2 \) for Function 5 and \( c = 4 \) for Function 6. #### Example Calculation for Function 5: \[ x = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 1 \cdot 2}}{2 \cdot 1}
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