+5 V 4.35 V- Ic1K FIGURE 5-55 (Exercise 5-3)

Introductory Circuit Analysis (13th Edition)
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Determine IC for a BJT given the circuit shown in Figure 5-55 (p. 250). IS =1.3 x 10-13 A; VT = 0.025 V.

**Figure 5-55 (Exercise 5-3): Transistor Circuit Diagram**

This diagram represents a simple transistor circuit. Here's an explanation of the components and connections:

- **Transistor:** The central component is a bipolar junction transistor (BJT). The emitter is connected to the ground, the base is supplied with 4.35 V, and the collector is connected to a +5 V power supply.

- **Voltage Labels:**
  - The base-emitter voltage is labeled as 4.35 V.
  - The collector-emitter voltage is noted as +5 V.

- **Current and Resistance:**
  - The current flowing through the collector is represented as \( I_C \).
  - A 1 KΩ resistor is placed between the collector terminal and the ground.

This configuration is typical for analyzing the behavior of BJTs in circuits, allowing the calculation of the current \( I_C \) and understanding the transistor's role in amplification or switching applications.
Transcribed Image Text:**Figure 5-55 (Exercise 5-3): Transistor Circuit Diagram** This diagram represents a simple transistor circuit. Here's an explanation of the components and connections: - **Transistor:** The central component is a bipolar junction transistor (BJT). The emitter is connected to the ground, the base is supplied with 4.35 V, and the collector is connected to a +5 V power supply. - **Voltage Labels:** - The base-emitter voltage is labeled as 4.35 V. - The collector-emitter voltage is noted as +5 V. - **Current and Resistance:** - The current flowing through the collector is represented as \( I_C \). - A 1 KΩ resistor is placed between the collector terminal and the ground. This configuration is typical for analyzing the behavior of BJTs in circuits, allowing the calculation of the current \( I_C \) and understanding the transistor's role in amplification or switching applications.
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Given PNP transistor shown

Is=1.3×10-13 AVT=0.025 v

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