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5) Using the trapezoida method, and the simpson's 1/3 rule mothers Compute for the area of the profile shown below. h₁ ha ha ha ha ha ha hit hill hiz hist 10 to 10 16 Line ABIs the base line of the irregular shaped lot. hi 6,20 h = 7020 hil 5,80 /h₂= 6.42 47=6188 122 123 to 16 LO h3=6,60 /h 4 = 6174 hs = 7,00 (0 10 ha 20 10 ha = 6,52 hio = 6,20 ·GOOD LUCK- 10 h12=5,66 = 6074 h13 = 5,00. 2/1/14= = 0.00 OF 16 hit

5) Using the trapezoida method, and the simpson's 1/3 rule mothers Compute for the area of the profile shown below. h₁ ha ha ha ha ha ha hit hill hiz hist 10 to 10 16 Line ABIs the base line of the irregular shaped lot. hi 6,20 h = 7020 hil 5,80 /h₂= 6.42 47=6188 122 123 to 16 LO h3=6,60 /h 4 = 6174 hs = 7,00 (0 10 ha 20 10 ha = 6,52 hio = 6,20 ·GOOD LUCK- 10 h12=5,66 = 6074 h13 = 5,00. 2/1/14= = 0.00 OF 16 hit

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Using the trapezoidal method and the simpson's 1/3 rule method, compute for the area of the profile shown below.

Line AB is the base line of the irregular shaped lot.

h1 = 6.20

h2 = 6.42

h3 = 6.60

h4 = 6.74

h5 =  7.00

h6 = 7.20

h7 = 6.80

h8 = 6.74

h9 = 6.52

h10 = 6.20

h11 = 5.80

h12 = 5.60

h13 = 5.00

h14 = 0.00

Kindly show a full and detailed solution, thank you!

5) Using the trapezoide method, and the simpson's 1/3 rule method Compute for the area of the profile shown below. 5 hi 122 123 h4 hs he hat he ha hit hill hiz his 10 10 to 16 10 10 10 Line ABIs the base line of the irregular shaped lot. hi 6, 20 h = 7020 hil 5,80 /1₂= 6.42 h3 = 6,60 14 = 6174 hs = 7/100 = 7/100 10 - 10 10 hiy h₁0 hit 16 17 = 6,88 h₁2 = 5,60 hi /h = 6074 • h13 = 5,00. =6,52714=0.00 = 6120 10 GOOD LUCK - hit 16 B
Transcribed Image Text:5) Using the trapezoide method, and the simpson's 1/3 rule method Compute for the area of the profile shown below. 5 hi 122 123 h4 hs he hat he ha hit hill hiz his 10 10 to 16 10 10 10 Line ABIs the base line of the irregular shaped lot. hi 6, 20 h = 7020 hil 5,80 /1₂= 6.42 h3 = 6,60 14 = 6174 hs = 7/100 = 7/100 10 - 10 10 hiy h₁0 hit 16 17 = 6,88 h₁2 = 5,60 hi /h = 6074 • h13 = 5,00. =6,52714=0.00 = 6120 10 GOOD LUCK - hit 16 B
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