5) Using the trapezoida method, and the simpson's 1/3 rule mothers Compute for the area of the profile shown below. h₁ ha ha ha ha ha ha hit hill hiz hist 10 to 10 16 Line ABIs the base line of the irregular shaped lot. hi 6,20 h = 7020 hil 5,80 /h₂= 6.42 47=6188 122 123 to 16 LO h3=6,60 /h 4 = 6174 hs = 7,00 (0 10 ha 20 10 ha = 6,52 hio = 6,20 ·GOOD LUCK- 10 h12=5,66 = 6074 h13 = 5,00. 2/1/14= = 0.00 OF 16 hit
5) Using the trapezoida method, and the simpson's 1/3 rule mothers Compute for the area of the profile shown below. h₁ ha ha ha ha ha ha hit hill hiz hist 10 to 10 16 Line ABIs the base line of the irregular shaped lot. hi 6,20 h = 7020 hil 5,80 /h₂= 6.42 47=6188 122 123 to 16 LO h3=6,60 /h 4 = 6174 hs = 7,00 (0 10 ha 20 10 ha = 6,52 hio = 6,20 ·GOOD LUCK- 10 h12=5,66 = 6074 h13 = 5,00. 2/1/14= = 0.00 OF 16 hit
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
Using the trapezoidal method and the simpson's 1/3 rule method, compute for the area of the profile shown below.
Line AB is the base line of the irregular shaped lot.
h1 = 6.20
h2 = 6.42
h3 = 6.60
h4 = 6.74
h5 = 7.00
h6 = 7.20
h7 = 6.80
h8 = 6.74
h9 = 6.52
h10 = 6.20
h11 = 5.80
h12 = 5.60
h13 = 5.00
h14 = 0.00
Kindly show a full and detailed solution, thank you!
![5) Using the trapezoide method, and the simpson's 1/3 rule method
Compute for the area of the profile shown below.
5
hi
122 123 h4 hs he hat he ha hit hill hiz his
10
10
to 16 10
10 10
Line ABIs the base line of the irregular shaped lot.
hi 6, 20
h = 7020
hil
5,80
/1₂= 6.42
h3 = 6,60
14 = 6174
hs = 7/100
= 7/100
10
-
10
10
hiy
h₁0
hit
16
17 = 6,88 h₁2 = 5,60
hi
/h = 6074 • h13 = 5,00.
=6,52714=0.00
= 6120
10
GOOD LUCK -
hit
16
B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb82b1bf-9ecb-4650-bc73-bb0c93237287%2Fe1291324-72a3-4af5-8caf-c099bf56a22c%2Fd0vs1me_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5) Using the trapezoide method, and the simpson's 1/3 rule method
Compute for the area of the profile shown below.
5
hi
122 123 h4 hs he hat he ha hit hill hiz his
10
10
to 16 10
10 10
Line ABIs the base line of the irregular shaped lot.
hi 6, 20
h = 7020
hil
5,80
/1₂= 6.42
h3 = 6,60
14 = 6174
hs = 7/100
= 7/100
10
-
10
10
hiy
h₁0
hit
16
17 = 6,88 h₁2 = 5,60
hi
/h = 6074 • h13 = 5,00.
=6,52714=0.00
= 6120
10
GOOD LUCK -
hit
16
B
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