5) There are two forces on the 1.00 kg box in the overhead view of figure at the right, but only one is shown. For F1 2.00 N, a = 3.00 m/s, and 0 = 40.0° find the magnitude of the second force. Answer: _N. Fill in the blanks by providing the final answers. In the box below please show how you found the final answers. end the to
5) There are two forces on the 1.00 kg box in the overhead view of figure at the right, but only one is shown. For F1 2.00 N, a = 3.00 m/s, and 0 = 40.0° find the magnitude of the second force. Answer: _N. Fill in the blanks by providing the final answers. In the box below please show how you found the final answers. end the to
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question 5 attached
![---
### Problem Statement
**5)**
There are two forces on the 1.00 kg box in the overhead view of the figure at the right, but only one is shown. For \( F_1 = 2.00 \, \text{N} \), \( a = 3.00 \, \text{m/s}^2 \), and \( \theta = 40.0^\circ \), find the magnitude of the second force.
Answer: __________ N.
Fill in the blanks by providing the final answers. In the box below please show how you found the final answers.
**Explanation**
In the given problem, a box with a mass of 1.00 kg is subjected to two forces. One force \( F_1 \), which has a magnitude of 2.00 N, is provided along with its direction. The desired acceleration \( a \) of the box is given as 3.00 m/s², and the angle \( \theta \) between the direction of the acceleration and the force \( F_1 \) is 40.0 degrees.
### Diagram
The provided figure shows a box with one force \( F_1 \) acting on it. The force \( F_1 \) is shown as a blue arrow pointing along the positive x-axis. An acceleration vector \( \vec{a} \) is shown as an orange arrow at an angle \( \theta = 40.0^\circ \) from the x-axis. Here is a detailed description of the diagram:
- A rectangular box is centered within a coordinate system with axes labeled \( x \) and \( y \).
- Force \( F_1 \) is shown as an arrow originating from the center of the box and directed horizontally to the right (positive x-axis).
- The acceleration vector \( \vec{a} \) is shown at an angle \( \theta \) = 40.0° from the positive x-axis.
### Solution
To solve for the magnitude of the second force, you should use the following steps:
1. **Resolve the Forces:**
- Resolve the known force \( F_1 \) into its components along the x-axis and y-axis.
\[
F_{1x} = F_1 = 2.00 \, \text{N}
\]
\[
F_{1y} = 0 \, \text](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe559c78b-2db2-49bb-be84-bfa794bcb4bb%2F9693d5b4-c652-4f54-a672-5819e032c302%2F77ihvbd.jpeg&w=3840&q=75)
Transcribed Image Text:---
### Problem Statement
**5)**
There are two forces on the 1.00 kg box in the overhead view of the figure at the right, but only one is shown. For \( F_1 = 2.00 \, \text{N} \), \( a = 3.00 \, \text{m/s}^2 \), and \( \theta = 40.0^\circ \), find the magnitude of the second force.
Answer: __________ N.
Fill in the blanks by providing the final answers. In the box below please show how you found the final answers.
**Explanation**
In the given problem, a box with a mass of 1.00 kg is subjected to two forces. One force \( F_1 \), which has a magnitude of 2.00 N, is provided along with its direction. The desired acceleration \( a \) of the box is given as 3.00 m/s², and the angle \( \theta \) between the direction of the acceleration and the force \( F_1 \) is 40.0 degrees.
### Diagram
The provided figure shows a box with one force \( F_1 \) acting on it. The force \( F_1 \) is shown as a blue arrow pointing along the positive x-axis. An acceleration vector \( \vec{a} \) is shown as an orange arrow at an angle \( \theta = 40.0^\circ \) from the x-axis. Here is a detailed description of the diagram:
- A rectangular box is centered within a coordinate system with axes labeled \( x \) and \( y \).
- Force \( F_1 \) is shown as an arrow originating from the center of the box and directed horizontally to the right (positive x-axis).
- The acceleration vector \( \vec{a} \) is shown at an angle \( \theta \) = 40.0° from the positive x-axis.
### Solution
To solve for the magnitude of the second force, you should use the following steps:
1. **Resolve the Forces:**
- Resolve the known force \( F_1 \) into its components along the x-axis and y-axis.
\[
F_{1x} = F_1 = 2.00 \, \text{N}
\]
\[
F_{1y} = 0 \, \text
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