5) There are two forces on the 1.00 kg box in the overhead view of figure at the right, but only one is shown. For F1 2.00 N, a = 3.00 m/s, and 0 = 40.0° find the magnitude of the second force. Answer: _N. Fill in the blanks by providing the final answers. In the box below please show how you found the final answers. end the to

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question

Question 5 attached

---

### Problem Statement

**5)** 

There are two forces on the 1.00 kg box in the overhead view of the figure at the right, but only one is shown. For \( F_1 = 2.00 \, \text{N} \), \( a = 3.00 \, \text{m/s}^2 \), and \( \theta = 40.0^\circ \), find the magnitude of the second force. 
Answer: __________ N. 
Fill in the blanks by providing the final answers. In the box below please show how you found the final answers.

**Explanation**

In the given problem, a box with a mass of 1.00 kg is subjected to two forces. One force \( F_1 \), which has a magnitude of 2.00 N, is provided along with its direction. The desired acceleration \( a \) of the box is given as 3.00 m/s², and the angle \( \theta \) between the direction of the acceleration and the force \( F_1 \) is 40.0 degrees.

### Diagram

The provided figure shows a box with one force \( F_1 \) acting on it. The force \( F_1 \) is shown as a blue arrow pointing along the positive x-axis. An acceleration vector \( \vec{a} \) is shown as an orange arrow at an angle \( \theta = 40.0^\circ \) from the x-axis. Here is a detailed description of the diagram:

- A rectangular box is centered within a coordinate system with axes labeled \( x \) and \( y \).
- Force \( F_1 \) is shown as an arrow originating from the center of the box and directed horizontally to the right (positive x-axis).
- The acceleration vector \( \vec{a} \) is shown at an angle \( \theta \) = 40.0° from the positive x-axis.

### Solution

To solve for the magnitude of the second force, you should use the following steps:

1. **Resolve the Forces:**
   - Resolve the known force \( F_1 \) into its components along the x-axis and y-axis.
     \[
     F_{1x} = F_1 = 2.00 \, \text{N}
     \]
     \[
     F_{1y} = 0 \, \text
Transcribed Image Text:--- ### Problem Statement **5)** There are two forces on the 1.00 kg box in the overhead view of the figure at the right, but only one is shown. For \( F_1 = 2.00 \, \text{N} \), \( a = 3.00 \, \text{m/s}^2 \), and \( \theta = 40.0^\circ \), find the magnitude of the second force. Answer: __________ N. Fill in the blanks by providing the final answers. In the box below please show how you found the final answers. **Explanation** In the given problem, a box with a mass of 1.00 kg is subjected to two forces. One force \( F_1 \), which has a magnitude of 2.00 N, is provided along with its direction. The desired acceleration \( a \) of the box is given as 3.00 m/s², and the angle \( \theta \) between the direction of the acceleration and the force \( F_1 \) is 40.0 degrees. ### Diagram The provided figure shows a box with one force \( F_1 \) acting on it. The force \( F_1 \) is shown as a blue arrow pointing along the positive x-axis. An acceleration vector \( \vec{a} \) is shown as an orange arrow at an angle \( \theta = 40.0^\circ \) from the x-axis. Here is a detailed description of the diagram: - A rectangular box is centered within a coordinate system with axes labeled \( x \) and \( y \). - Force \( F_1 \) is shown as an arrow originating from the center of the box and directed horizontally to the right (positive x-axis). - The acceleration vector \( \vec{a} \) is shown at an angle \( \theta \) = 40.0° from the positive x-axis. ### Solution To solve for the magnitude of the second force, you should use the following steps: 1. **Resolve the Forces:** - Resolve the known force \( F_1 \) into its components along the x-axis and y-axis. \[ F_{1x} = F_1 = 2.00 \, \text{N} \] \[ F_{1y} = 0 \, \text
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
First law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON