(5) The wave function for a particle is given by: (2) = Ae /L for x2 0, where A and L are constants, and L >0. %3D (r) = 0 for r < 0. (a) Find the value of the constant A, as a function of L. A useful integral is: fe-K=dr = -ke-K, where K is a constant. (b) What is the probability of finding the particle in the range - 10 L
(5) The wave function for a particle is given by: (2) = Ae /L for x2 0, where A and L are constants, and L >0. %3D (r) = 0 for r < 0. (a) Find the value of the constant A, as a function of L. A useful integral is: fe-K=dr = -ke-K, where K is a constant. (b) What is the probability of finding the particle in the range - 10 L
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Parts d-e please

Transcribed Image Text:(5) The wave function for a particle is given by:
(r) = Ae /L for a > 0, where A and L are constants, and L > 0.
v(r) = 0 for r < 0.
%3D
(a) Find the value of the constant A, as a function of L. A useful integral is: fe-K= dx = -ke-Kz,
where K is a constant.
(b) What is the probability of finding the particle in the range - 10 L < r < -L?
(c) What is the probability of finding the particle in the range 0 <r< L?
(d) What is the expectation value (2) for the particle, when the particle is in the range 0 <r< L?
A useful integral is: Sudv = uv - Jv du.
(e) Suppose the total energy E of the particle is:
E =
2mL2
What is the potential energy of the particle, as a function of m and L? Assume non-relativistic motion.
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