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5) The graph of the quadratic function f(x) = (x - 1)(x + 5) intersects the y-axis (0, c). The vertex of th function is (-2,-6.75). The equation has two x values where f(x) = -6 and the first x value is at x = −3 a) Find the value of c. (0) = 2/1 (0-1) (075) (1)(5) (M²) -5 b) Write down the equation for the axis of symmetry of the graph. 2 P(x) = 3/1 (x-7)(x + 5) 3/ = 3/4x²+5x-x-5 c) Write down the x-intercepts of t graph. 6 * x-1=0 X=1 d) Draw the graph of y = f(x) for -7 ≤ x ≤ 3 and -7 ≤ y ≤ 12 (4₂) x²+x-5 X+5=0 x= -√ 3.75 e) Use the symmetry of the graph to show that the second solution is x = -1.

5) The graph of the quadratic function f(x) = (x - 1)(x + 5) intersects the y-axis (0, c). The vertex of th function is (-2,-6.75). The equation has two x values where f(x) = -6 and the first x value is at x = −3 a) Find the value of c. (0) = 2/1 (0-1) (075) (1)(5) (M²) -5 b) Write down the equation for the axis of symmetry of the graph. 2 P(x) = 3/1 (x-7)(x + 5) 3/ = 3/4x²+5x-x-5 c) Write down the x-intercepts of t graph. 6 * x-1=0 X=1 d) Draw the graph of y = f(x) for -7 ≤ x ≤ 3 and -7 ≤ y ≤ 12 (4₂) x²+x-5 X+5=0 x= -√ 3.75 e) Use the symmetry of the graph to show that the second solution is x = -1.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can someone please help with B, D, and E please? Thank you. 

3 5) The graph of the quadratic function f(x) = (x - 1)(x + 5) intersects the y-axis (0, c). The vertex of th function is (−2, −6.75). The equation has two x values where f(x) = -6 and the first x value is at x = −3 4 a) Find the value of c. (0) = 3 (0-1) (075) (-4) (5) (MI) उ.-5 zen. 4 b) Write down the equation for the axis of symmetry of the graph. f(x) = 3/1 (XT) (x + 5) 2 ỉ xe+5x-x-5 c) Write down the x-intercepts of the graph. (lx)=0 * x-1=0 X=1 d) Draw the graph of y = f(x) for -7 ≤ x ≤ 3 and -7 ≤ y ≤ 12 (41) = 2 32 x ²² +#x-5 3.75 (42) x+5=0 x = -√ X e) Use the symmetry of the graph to show that the second solution is x = -1.
Transcribed Image Text:3 5) The graph of the quadratic function f(x) = (x - 1)(x + 5) intersects the y-axis (0, c). The vertex of th function is (−2, −6.75). The equation has two x values where f(x) = -6 and the first x value is at x = −3 4 a) Find the value of c. (0) = 3 (0-1) (075) (-4) (5) (MI) उ.-5 zen. 4 b) Write down the equation for the axis of symmetry of the graph. f(x) = 3/1 (XT) (x + 5) 2 ỉ xe+5x-x-5 c) Write down the x-intercepts of the graph. (lx)=0 * x-1=0 X=1 d) Draw the graph of y = f(x) for -7 ≤ x ≤ 3 and -7 ≤ y ≤ 12 (41) = 2 32 x ²² +#x-5 3.75 (42) x+5=0 x = -√ X e) Use the symmetry of the graph to show that the second solution is x = -1.
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