5-The four pairs share a common middle hop with a transmission capacity of R = 400 Mbps. The four links from the servers to the shared link have a transmission capacity of Rs 70 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of Rc= 80 Mbps. Y A. What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fairly shared (divides its transmission rate equally)? B. Which link is the bottleneck link? Format as Rc, Rs, or R?

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A: Q. What is the value of the golden ratio ᶲ  ?

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Q: How might a biased exponent be helpful?

A: Answer of given question is in next step.

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A: The answer is

Q: . The result of (00001110)2+ (1C)16 O (52)8 All answers are correct O (52)16 111 11 01 1

A: 00001110 2 = 0E16 1C16 = 00011100

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A: Dear Student, The answer to your question is given below -

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A: This is a question on mathematical induction.

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A:

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A: Lets see the solution.

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A:

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Q: How might a biased exponent be helpful?

A: Here is the explanation regarding the biased exponent: