5) The bar shown has a circular cross section with a 0.002 m diameter and its modulus of elasticity is E = 86.6 GPa. It is subjected to a uniformly distributed axial force of q =75 kN/m and an axial force of F= 15 kN. a. Calculate the axial force P in the bar as a function of .x. b. Calculate the bar's total change in length. c. Calculate the reaction force at the fixed end. 9 L=0.8 m F x

Elements Of Electromagnetics
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5) The bar shown has a circular cross section with a 0.002 m diameter and its modulus of elasticity
is E= 86.6 GPa. It is subjected to a uniformly distributed axial force of q =75 kN/m and an axial
force of F= 15 kN.
a. Calculate the axial force P in the bar as a function of x.
b. Calculate the bar's total change in length.
c. Calculate the reaction force at the fixed end.
L=0.8 m
F
x
Transcribed Image Text:5) The bar shown has a circular cross section with a 0.002 m diameter and its modulus of elasticity is E= 86.6 GPa. It is subjected to a uniformly distributed axial force of q =75 kN/m and an axial force of F= 15 kN. a. Calculate the axial force P in the bar as a function of x. b. Calculate the bar's total change in length. c. Calculate the reaction force at the fixed end. L=0.8 m F x
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